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ella [17]
3 years ago
12

What is the equation of the line of reflection in the following coordinate plane?Angle abc has the points (4, -1), (5, 1), and (

3, 3) and the other angle has the points (-2, -1), (-1, 3), and (-3, 1)
x = 0
y = 2
x = 1
y = 1
Mathematics
1 answer:
AlladinOne [14]3 years ago
5 0

Answer:Question 1: Option B:

Question 2: Option D:

Solution:

Question 1:

The point on the given line are (2, 4) and (4, –2).

Slope of the given line:

m = –3.

Slope of perpendicular line = –1 ÷ Slope of the given line

Slope of perpendicular line =

Perpendicular line passing through the point (3, 1).

Slope -intercept form using point slope formula,

Option B is the correct answer.

Question 2:

The point on the given line are (0, –3) and (2, 3).

Slope of the given line:

m = 3.

Slope of parallel lines are equal.

Slope of parallel line =3

parallel lines passing through the point (–1, –1).

Point slope formula:

Option D is the correct answer.Question 1: Option B:

Question 2: Option D:

Solution:

Question 1:

The point on the given line are (2, 4) and (4, –2).

Slope of the given line:

m = –3.

Slope of perpendicular line = –1 ÷ Slope of the given line

Slope of perpendicular line =

Perpendicular line passing through the point (3, 1).

Slope -intercept form using point slope formula,

Option B is the correct answer.

Question 2:

The point on the given line are (0, –3) and (2, 3).

Slope of the given line:

m = 3.

Slope of parallel lines are equal.

Slope of parallel line =3

parallel lines passing through the point (–1, –1).

Point slope formula:

Option D is the correct answer.Question 1: Option B:

Question 2: Option D:

Solution:

Question 1:

The point on the given line are (2, 4) and (4, –2).

Slope of the given line:

m = –3.

Slope of perpendicular line = –1 ÷ Slope of the given line

Slope of perpendicular line =

Perpendicular line passing through the point (3, 1).

Slope -intercept form using point slope formula,

Option B is the correct answer.

Question 2:

The point on the given line are (0, –3) and (2, 3).

Slope of the given line:

m = 3.

Slope of parallel lines are equal.

Slope of parallel line =3

parallel lines passing through the point (–1, –1).

Point slope formula:

Option D is the correct answer.Question 1: Option B:

Question 2: Option D:

Solution:

Question 1:

The point on the given line are (2, 4) and (4, –2).

Slope of the given line:

m = –3.

Slope of perpendicular line = –1 ÷ Slope of the given line

Slope of perpendicular line =

Perpendicular line passing through the point (3, 1).

Slope -intercept form using point slope formula,

Option B is the correct answer.

Question 2:

The point on the given line are (0, –3) and (2, 3).

Slope of the given line:

m = 3.

Slope of parallel lines are equal.

Slope of parallel line =3

parallel lines passing through the point (–1, –1).

Point slope formula:

Option D is the correct answer.Question 1: Option B:

Question 2: Option D:

Solution:

Question 1:

The point on the given line are (2, 4) and (4, –2).

Slope of the given line:

m = –3.

Slope of perpendicular line = –1 ÷ Slope of the given line

Slope of perpendicular line =

Perpendicular line passing through the point (3, 1).

Slope -intercept form using point slope formula,

Option B is the correct answer.

Question 2:

The point on the given line are (0, –3) and (2, 3).

Slope of the given line:

m = 3.

Slope of parallel lines are equal.

Slope of parallel line =3

parallel lines passing through the point (–1, –1).

Point slope formula:

Option D is the correct answer.

Step-by-step explanation:

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sladkih [1.3K]

D is halfway between A and B

so the coordinates of D are (2,2)

E is halfway between A and C so the coordinates of E are (-1,1)

now you need to find the gradient/slope of DE and BC using the formula:

\frac{y2 - y1}{x2 - x1}

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>

SUB IN COORDINATES OF D AND E

\frac{1 - 2}{ - 1 - 2}

therefore the gradient of DE is 1/3.

<h3><u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>

<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>

<em>\frac{ - 2 - 0}{ - 3 - 3}</em>

therefore the gradient of BC is -2/-6 which simplifies to 1/3.

<h3>therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>

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