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Nadusha1986 [10]
3 years ago
9

Find the TWO integers whos product is -12 and whose sum is 1m​

Mathematics
2 answers:
svetoff [14.1K]3 years ago
5 0

Answer:

\rm Numbers = 4 \ and \ -3.

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}

Hence the numbers are 4 and -3.

irga5000 [103]3 years ago
3 0

Answer:

-3,4 are the TWO integers whos product is -12 and whose sum is 1.

Step-by-step explanation:

<em>-3</em><em>×</em><em>4</em><em>=</em><em>1</em><em>2</em>

<em>-3</em><em>+</em><em>4</em><em>=</em><em>1</em>

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\bold{[ \ Answer \ ]}

\boxed{\bold{F \ = \ -\frac{21}{19} }}

\bold{[ \ Explanation \ ]}

  • \bold{Solve: \ f \ - \ 20f \ = \ 21}

-----------------------------------

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