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jenyasd209 [6]
4 years ago
14

Why does hot air rise and cold air sink??

Chemistry
2 answers:
Ray Of Light [21]4 years ago
7 0

Explanation:

In hot air, molecules have more kinetic energy and due to this they move from one place to another. As a result, there occurs more number of collisions between the molecules. Due to this molecules of hot air tend to rise.

Whereas when air is cold then its molecules are closer to each other. As a result, they do not have enough kinetic energy and they do not move from their initial position.

Hence, cold air sinks because of lack of movement in its molecules.

DaniilM [7]4 years ago
3 0
<span>Hot air rises because the molecules are further apart so it can take more room. </span>Which makes hot air lighter than cold air. Cold air sinks because it has more molecules but in the same amount of room. 
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Please help me out with this assignment
liberstina [14]

Answer:

1. 7 meters

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8 0
4 years ago
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl
Cerrena [4.2K]

Answer:

0.077 M

Explanation:

Molarity is the representation of the solution.

Molarity:

It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                    M = moles of solute / Liter of solution . . . . . . . . . . (1)

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution =  100 g = 100 mL

Volume of Solution in L =  100 mL / 1000

Volume of Solution =  0.1 L

molar mass of NaCl = 58.44 g/mol

Now to find number of moles of Nacl

               no. of moles of NaCl = mass of NaCl / molar mass

               no. of moles of NaCl =  0.45g / 58.44 g/mol

               no. of moles of NaCl =  0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0
4 years ago
"The occurrence of the all-or-none ________________ results from depolarization in response to rapid entry of ____________ ions
Leno4ka [110]

Answer:

The correct answer is

B.action potential; sodium

Explanation:

Action potential

Nerve action potentials are initiated and propagated in an all or nothing fashion. The all-or nothing action potential is initiated when the membrane potential threshold value is reached

Sodium

Voltage-gated Na⁺ ions membrane channels open enabling an influx of sodium ions to rapidly enter the cell, raising the membrane potential up to +40 mV

Depolarization  in the neuron is based ion exchange channels opening to allow the rapid influx of sodium ions (Na⁺) and the efflux of potassium ions (K⁺)

The neuronal responds rapidly and for short periods to the activation of an ion channel receptor by a drug or natural neurotransmitter is rapid rel

8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIST
Free_Kalibri [48]

Answer:

The average speed must be 30mph so this means the car traveled for 2hrs 60/30

7 0
3 years ago
Reaction enthalpy for ethanol oxidation, C2H5OH+3O2 -&gt; 2CO2 + 3H2O is 1257 kJ/mole. Energy content per mol fuel ______kJ Ener
MArishka [77]

Answer:

Energy content per mol fuel 1257 kJ.

Energy content per gram fuel = 27.33  kJ

Energy released per mol carbon dioxide gas formed is 628.5 kJ

Energy released per mol oxygen gas consumed= 419 kJ

Moles of carbon dioxide gas formed per 1000 kJ energy released is 1.591.

Explanation:

C_2H_5OH+3O_2\rightarrow 2CO_2 + 3H_2O,\Delta H= 1257 kJ/mol

1) Energy released per mole or fuel that is ethanol :

1mol \times 1257 kJ/mol=1257 kJ

2) Mass of 1 mole of ethanol = 46 g

46 grams of ethanol produces 1257 kJ of energy

Energy content per gram fuel :

\frac{1257 kJ}{46 g}=27.33 kJ/g

3) Energy released when 2 moles of carbon dioxide are formed = 1257 kJ

Energy released per mol of carbon dioxide formed:

\frac{1}{2}\times 1257 kJ/mol=628.5 kJ/mol

4) Energy released when 3 moles of oxygen gas are consumed = 1257 kJ

Energy released per mol of oxygen gas consumed:

\frac{1}{3}\times 1257 kJ/mol=419 kJ/mol

5) Energy released when 2 moles of carbon dioxide are formed = 1257 kJ

Moles of carbon dioxide gas formed per kilo Joule of energy:

\frac{2}{1257} mol

Moles of carbon dioxide gas formed when 1000 kJ of heat is released:

\frac{2}{1257} \times 1000 mol=1.591 mol

5 0
4 years ago
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