Molarity is measured in moles per Liter. If there are 1.35 g/mL, find out how many grams there are in a liter of solution.
If there are 1000 mL in one liter, we can multiply by 1000 to get g/L
1.35 g/mL x 1 Liter/1000 mL = 1350 g per Liter of solution
By weight, the NaOH is 33% or .33
1350 g x .33 = 445.5 g of NaOH
Molar mass of NaOH is 39.997 g
445.5 g x 1 mol NaOH/39.997 g = 11.13833538 moles per Liter
Rounded to significant figures, the answer is 11 mol/L NaOH
Answer:
92gm
Explanation:
Atomic mass of Mg=24g=1 mole of Mg
∴ 24g =1 mole of Mg contain 6.022×10^23 atom
∴ 6gm contains 246.022×1023×6
=4×6.022×10^23 atoms
Now according to question, there are 6.022×1023 atoms of Na
23gm of Na contains 6.022×10^23 atoms
∴6.022×4×10^23 atoms of Na weighs 23×6.022×10^23×4/6.022×10^23⇒92gm
Explanation:
When solid cadmium sulfide reacts with an aqueous solution of sulfuric acid then the reaction will be as follows.

Hence, ionic equation for this reaction is as follows.

Therefore, net ionic equation for this reaction is as follows.
