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beks73 [17]
3 years ago
8

"The occurrence of the all-or-none ________________ results from depolarization in response to rapid entry of ____________ ions

into the neuron A. resting potential; sodium B.action potential; sodium C.resting potential; potassium D.action potential; potassium E.hormonal response; potassium F. hormonal response; sodium"
Chemistry
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

The correct answer is

B.action potential; sodium

Explanation:

Action potential

Nerve action potentials are initiated and propagated in an all or nothing fashion. The all-or nothing action potential is initiated when the membrane potential threshold value is reached

Sodium

Voltage-gated Na⁺ ions membrane channels open enabling an influx of sodium ions to rapidly enter the cell, raising the membrane potential up to +40 mV

Depolarization  in the neuron is based ion exchange channels opening to allow the rapid influx of sodium ions (Na⁺) and the efflux of potassium ions (K⁺)

The neuronal responds rapidly and for short periods to the activation of an ion channel receptor by a drug or natural neurotransmitter is rapid rel

Anestetic [448]3 years ago
4 0

Answer:

B. action potential; sodium.

Explanation:

Action potential occurs when the membrane potential of a specific cell location rapidly rises and falls.

These are generated by special types of voltage-gated ion channels embedded in a cell's plasma membrane. They are shut when the membrane potential is near the resting potential of the cell, but they open rapidly if the membrane potential increases to a defined threshold voltage, depolarising the membrane potential, this then allows the inward flow of sodium ions, which changes the electrochemical gradient.

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A truck traveled at a constant speed for 6 hours. Then, it
gavmur [86]

Answer:

2.4 hrs

Explanation:

The constant speed of the truck for 6 hrs can be calculated by: speed=distance/time. Speed =(876-228)/6=648/6=108m/s. So the decreased speed = (108-13)=95m/h. Now, speed =distance /time We get 95m/h = 228/t. t=228/95 hrs = 2.4 hrs PLEASE MARK ME THE BRAINLIEST!!

7 0
3 years ago
Read 2 more answers
Adding O2 to the reaction 6CO2 + 6H2O <---> C6H12O6 + 6O2, WHICH WAY WILL THE REACTION SHIFT?
Alex73 [517]

Increase in Oxygen shift the equilibrium towards reactant side.

<u>Explanation:</u>

6CO₂ + 6H₂O ⇄ C₆H₁₂O₆ + 6O₂

This is the reaction occurs in the photosynthesis of plants by means of sunlight. In this case, if the concentration of Oxygen increases or adding more oxygen to the product side will shift the equilibrium towards the reactant side according to the Le Chatlier's principle, which adjusts the equilibrium by itself for any changes that is increase or decrease in pressure, temperature or concentration of reactants or products.

5 0
3 years ago
1. What is the molarity of a solution which contains 0.256 mol of a substance dissolved in 143 mL of solution.
LenaWriter [7]

Answer:

The equation for molarity is moles/liter for the first question you would do 0.256/0.143 liters to get 1.790 mol/L

Explanation:

The second problem you would do need to find the moles of NaCl which you would do by doing 4.89 g/58.44g/mol= 0.08367 then do 0.08367/0.600= 0.139 mol/L

The third problem would be the same steps as the second one.

The fourth problem would be (0.460M)(5.50L)= 2.53 moles

4 0
3 years ago
Which of the following describes a double bond between two carbon atoms?
BlackZzzverrR [31]
Im pretty sure the answer is 4 but not 100 percent
5 0
3 years ago
Read 2 more answers
For a lake in Michigan, researchers have determined that largemouth bass feed on smaller fish, which in turn feed on zooplankton
allsm [11]

Answer:

the expected decline in largemouth bass is 3,000 kg.

Option d) 3,000 kg is the correct answer.

Explanation:

Given the data in the question;

In 2016, there was 600,000 kg of zooplankton in the lake.

In 2017, an accidental runoff of insecticide near the lake caused a 50 percent decline of the zooplankton population in the lake.

Now,

The remaining mass of zooplankton  after the 50% decline will be;

⇒ 600,000 kg zooplankton  × 50%

⇒ 600,000 × 50/100

⇒ 300,000 kg of zooplankton

Now, with 10 percent trophic efficiency;  smaller fish directly feed on zooplankton; decline in smaller fish mass will be;

⇒ 300,000 kg × 10%

⇒ 300,000 × 10/100

⇒  30000 kg

Finally, with 10 percent trophic efficiency, largemouth bash directly feed on smaller fish, so the expected decline in mass of largemouth bash will be;

⇒ 30000 kg × 10%

⇒ 30000 kg × 10/100

⇒ 3,000 kg

Therefore, the expected decline in largemouth bass is 3,000 kg.

Option d) 3,000 kg is the correct answer.

7 0
3 years ago
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