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alexandr402 [8]
3 years ago
11

Balance the equation 2kclo3 3o2 + kcl

Chemistry
1 answer:
sergij07 [2.7K]3 years ago
5 0
Answer is 2KClO3 3O2 + 2KCl
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Living organisms/chemical processes that support life

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3 years ago
Determine the empirical formula of kevlar, used in making bullet proof vests, is 70.6% c, 4.2% h, 11.8% n and 13.4% o.
Likurg_2 [28]

Assuming a basis of 100 g of Kevlar, therefore the masses are:

C = 70.6 g

H = 4.2 g

N = 11.8 g

O = 13.4 g

 

We know the molar masses are:

C = 12.01, H = 1.008, N = 14.01, O = 16.00

 

Calculating for the moles per element:

C = 70.6 / 12.01 = 5.88 mol

H = 4.2 / 1.008 = 4.17 mol

N = 11.8 / 14.01 = 0.84 mol

O = 13.4 / 16 = 0.84 mol

 

To get the empirical formula, the next step is to divide everything by the smallest moles = 0.84. So:

C = 7

H = 5

N = 1

O = 1

 

Hence the empirical formula is:

C7H5NO

3 0
4 years ago
Write the complete balanced equation for Manganese & sulfuric acid --> Manganese (II) sulfate & water & sulfur di
jok3333 [9.3K]

Answer:

I kinda forgot. I'm sorry if I didn't answer your question.

Explanation:

7 0
3 years ago
A catalyst can increase the rate of a reaction ________. Select one: a. by increasing the overall activation energy (Ea) of the
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Answer:

by providing an alternative pathway with a lower activation energy

Explanation:

Cataysts are the substances that neither consumed nor produced during a chemical reaction, but increase the rate of the reaction.

So, catalysts remain chemically unchnaged after the completion of the reaction.

For a reaction to occur, reactants molecule must collide and successful collisions lead to product formation.

A certain minimum amount of energy is required for successful collision. This minimum amounr of energy is called activation energy.

One way to increase speed of reaction is to provide energy to the reactants  and other way to increase speed is to provide alternate pathway with lower activation energy.

Catalyst increases a rate of reaction by providing an alternate pathway with lower activation energy.

Therefore, the correct option is option b 'by providing an alternative pathway with a lower activation energy'

5 0
4 years ago
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