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3 years ago

Balance the equation 2kclo3 3o2 + kcl

Chemistry

1 answer:

sergij07 [2.7K]3 years ago

5 0

Answer is 2KClO3 3O2 + 2KCl

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myrzilka [38]

Answer:

0.305 mol

Explanation:

Ca(NO) is not a molecule. I think you meant to type Ca(NO3)2, which is calcium nitrate.

The moles of a compound is equal to is mass divided by its molar mass.

The molar mass of Ca(NO3)2 is 164.09 g/mol.

50.0 / 164.09 = 0.305

6 0

2 years ago

What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin

Contact [7]

Answer: The total volume of the gaseous products is 1044.29 L

Explanation:

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = $\frac{1}{22.4}\times 116=5.18mol$ of butane

The chemical equation for the combustion of butane follows:

$2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)$

For carbon dioxide:

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = $\frac{8}{2}\times 5.18=20.72mol$ of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

For water vapor:

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = $\frac{10}{2}\times 5.18=25.9mol$ of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0

3 years ago

Help me with this question!!

skelet666 [1.2K]

Nitrogen is ...19.7
flourine is 80.3...
hope this helps!

8 0

4 years ago

What volume would 0.735 moles of O2 gas occupy at STP

tatiyna

Answer:

16.5 dm³

Explanation:

Data Given:

no. moles of O₂ = 0.735 moles

volume of O₂ = ?

Solution:

Now

we have to find volume of O₂ gas

Formula used for this purpose

No. of moles = Volume / molar volume

where

molar volume at STP for Oxygen (O₂) = 22.4 dm³/mol

No. of moles O₂ = Volume of O₂ / 22.4 dm³/mol . . . . . .(1)

Put values in equation 1

0.735 = Volume of O₂ / 22.4 dm³/ mol

rearrange above equation

Volume of O₂ = 0.735 x 22.4 dm³/ mol

Volume of O₂ = 16.5 dm³

So,

the volume of O₂ at STP is 16.5 dm³

6 0

3 years ago

Is the chemical equation NH3(g)+O2(g)→NO(g)+H2O(l) balanced?

umka2103 [35]

Answer:

yes

Explanation:

5 0

3 years ago