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3 years ago

What’s the equation for this

Mathematics

2 answers:

LekaFEV [45]3 years ago

8 0

<h2>Answer:</h2>

Hope it work for u

<h2>Step-by-step explanation:</h2>

We can make points from the given figure as ,

1 point =(x1, y1)=(-2, -3)

2nd point =(x2, y2)= (0, -6)

3rd point = (x3, y3)=(2 , -9)

Now the equation of line is,

<h2>Y=m X+ c where m is slope and c is constant </h2>

now two point formula of slope is ,

putting points in it we get

m=(-6-(-3))/(0-(-2)

m=-3/2 is slope

Now to find C putt the value of m and 3rd point in equation of line we get

y3=m(x3)+c

-9=(-3/2)(2) +c

C= -9+3

C=-6 is value of c

Now at last putt the value of C and m in equation of line we get the required equation ,

Anuta_ua [19.1K]3 years ago

4 0

.........................

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Simplify cubed 5 -10/27

MAXImum [283]

The correct answer for the given expression is 99.22.

<h3>What is an expression?</h3>

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication and division

The expression will be solved as:-

E = $({5 -\dfrac{10}{27}})^3$

E = $(\dfrac{135-10}{27})^3$

E = $\dfrac{125}{27}^3$

E = 99.22

Therefore the correct answer for the given expression is 99.22.

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2 years ago

Evaluate the expression

Alecsey [184]

I am pretty sure it is 30. Hope it helps!!

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Please help me with this

shusha [124]

Answer:

The one one the left is 1/2 , the one on the right is 8/25

Step-by-step explanation:

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2 years ago

Select the solution(s) of log2x=1−log(x+4).

mart [117]

Step-by-step explanation:

log2x = 1 - log(x+4)

log2x = log10 - log(x+4)

log2x = log[10/(x+4)]

2x = 10/(x+4)

2x(x+4) = 10

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÷2 both sides of equation

x² + 4x - 5 = 0

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3 years ago

Find the magnitude of WX for W(-2, 8, -3) and X(1, 4, -1)

zheka24 [161]

The magnitude of WX is $\sqrt{29}$ ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

$X=(x_{1},y_{1},z_{1})$
$Y=(x_{2},y_{2},z_{2})$

is IXYI = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}$

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ $x_{1}$ = -2 and $x_{2}$ = 1

∴ $y_{1}$ = 8 and $y_{2}$ = 4

∴ $z_{1}$ = -3 and $z_{2]$ = -1

- Substitute these values in the rule above

∵ IWXI = $\sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}$

∴ IWXI = $\sqrt{29}$

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