Answer:
Step-by-step explanation:
a.
first number is 1000-1+9=1008
9)1000(1
9
-------
10
9
-----
10
9
----
1
----
last number is 9999
9| 9999
---------
1111 |0
--------
9999=1008+(n-1)9
9999-1008=(n-1)9
n-1=8991/9=999
n=999+1=1000
b.
first digit=1000
last digit=9999-1=9998
2 |9999
---------
|4999|1
9998=1000+(n-1)2
(n-1)2=9998-1000=8998
n-1=4499
n=4499=1=5000
c.not sure
d.
total numbers=9000
9999=1000+(n-1)1
9999-1000=n-1
n=8999+1=9000
numbers divisible by 3=3000
first number=1002
last number=9999
9999=1002+(n-1)3
(n-1)3=9999-1002=8997
n-1=2999
n=2999+1=3000
numbers not divisible by 3=9000-3000=6000
e.
numbers divisible by 5=1800
first number=1000
last number=9995
9995=1000+(n-1)5
(n-1)5=9995-1000=8995
n-1=1799
n=1799+1=1800
numbers divisible by 7=1286
7 | 1000
---------
| 142-6
1000-6+7=1001
7 | 9999
|---------
1428-3
9999-3=9996
first digit=1001
last digit=9996
9996=1001+(n-1)7
(n-1)7=9996-1001=8995
n-1=1285
n=1285+1=1286
numbers divisible by 35=257
first digit=1015
35 ) 1000 ( 28
70
----
300
280
------
20
---
1000-20+35=1015
35)9999(285
70
----
299
280
-----
199
175
----
24
----
last digit=9999-24=9975
9975=1015+(n-1)35
(n-1)35=9975-1015=8960
n-1=8960/35=256
n=257
reqd. numbers=1800+1286-257=3019
Hey there Fish Girl!
So, if
![\left[\begin{array}{ccc}1/4 \end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2F4%20%5Cend%7Barray%7D%5Cright%5D%20%20%20)
equals 50 miles, then we would do this multiplied by . . . .
So, if we would want to go to 3 whole, we would then have to go to the number 3 of course. So then, we do
![\left[\begin{array}{ccc}4*3=12\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%2A3%3D12%5Cend%7Barray%7D%5Cright%5D%20%20%20)
and then from this, we would have to multiply this my 50.
The reason to why we would have to do this is because 1/4 of a mile is 50, so then, sense we are trying to get to the number 3, then, from doing this,we would determine a figure out how many miles this would conclude to be.
![\left[\begin{array}{ccc}12*50\end{array}\right] =\left[\begin{array}{ccc}\boxed{\boxed{600}} \ so \ far!\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D12%2A50%5Cend%7Barray%7D%5Cright%5D%20%20%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B600%7D%7D%20%5C%20so%20%5C%20far%21%5Cend%7Barray%7D%5Cright%5D%20)
So, now, we have covered 3 as a whole, then we would have to see how
3/8 and also
1/4 can relate to each other.
So, in this case,
So, most likely, it would stay the same as it is,
1/4 because this is almost half to.
SO ALL WE WOULD NEED TO DO NOW IS TO ADD . . . . .
![\left[\begin{array}{ccc}\left[\begin{array}{ccc}\boxed{\boxed{600+50 \ or \frac{1}{4}=650}} \end{array}\right]\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%5Cboxed%7B600%2B50%20%5C%20or%20%20%5Cfrac%7B1%7D%7B4%7D%3D650%7D%7D%20%5Cend%7Barray%7D%5Cright%5D%5Cend%7Barray%7D%5Cright%5D%20%20%20)
YOUR CORRECT AND FINAL ANSWER TO THIS QUESTION WOULD BE. . . .
![\left[\begin{array}{ccc}650 \ miles\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D650%20%5C%20miles%5Cend%7Barray%7D%5Cright%5D%20%20%20)
Hope this helps you fish Girl! :)
<h3>Answer: Approximately 191 bees</h3>
================================================
Work Shown:
One way to express exponential form is to use
y = a*b^x
where 'a' is the initial value and 'b' is linked to the growth rate.
Since we're told 34 bees are there initially, we know a = 34.
Then after 4 days, we have 48 bees. So we can say,
y = a*b^x
y = 34*b^x
48 = 34*b^4
48/34 = b^4
24/17 = b^4
b^4 = 24/17
b = (24/17)^(1/4)
b = 1.090035
Which is approximate.
The function updates to
y = a*b^x
y = 34*(1.090035)^x
------------------------
As a way to check to see if we have the right function, plug in x = 0 and we find:
y = 34*(1.090035)^x
y = 34*(1.090035)^0
y = 34*(1)
y = 34
So there are 34 bees on day 0, ie the starting day.
Plug in x = 4
y = 34*(1.090035)^x
y = 34*(1.090035)^4
y = 34*1.4117629
y = 47.9999386
Due to rounding error we don't land on 48 exactly, but we can round to this value.
We see that after 4 days, there are 48 bees.
So we confirmed the correct exponential function.
------------------------
At this point we can find out how many bees there are expected to be after 20 days.
Plug in x = 20 to get
y = 34*(1.090035)^x
y = 34*(1.090035)^20
y = 190.672374978452
Round to the nearest whole number to get 191.
There are expected to be roughly 191 bees on day 20.
Answer:
[ext]T(x) = 2C / Speed[/ext]
Step-by-step explanation:
[ext]Time taken for the Ranger to get to the car = Sum total time taken to travel in the forest and on the road[/ext]
Since [ext]distance of the Ranger to the car = C[/ext]
[ext]Time taken = distance/speed[/ext]
[ext]Total Time taken T(x) = 2 * C / speed[/ext]
T(x) = 2C / speed
Answer:
B
Step-by-step explanation:
We can divide using the calculator by entering in 59, 584 first followed by 14 before the division sign.
We can also perform long division:
__<u>4256_</u>____
14 | 59, 584
<u> -56__</u>__
35
<u> -28____</u>
78
<u> -70_</u>___
84
<u> -84_</u>___
0
