NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by
The sea level is represented by h = 0, therefore, to find the corresponding time when h splashes into the ocean we have to solve for t the following equation:
Using the quadratic formula, the solution for our problem is
The rocket splashes after 26.845 seconds.
The maximum of this function happens at the root of the derivative. Differentiating our function, we have
The root is
Then, the maximum height is
1029.99 meters above sea level.
Answer:
in the simplest term is:
Step-by-step explanation:
Given the expression
Thus, solving to reduce to the simplest term
LCM of 15, 2: 30
Adjusting fraction based on the LCM
so the expression becomes
Apply the fraction rule: 
Add the numbers: 8+15 = 23
Therefore, in the simplest term is:
Answer:
The horizontal shift is to the left by 2 units and the vertical shift is down 3 units for this function.
I hope I was able to help!
Step-by-step explanation:
Hey!
Hope this helps...
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The first thing we know is that all the answers equal 99, so we cannot cross any answer off, however, what we want to know is what answer (after distribution) looks like 36 + 63...
A.) 11(3 + 6) > 33 + 66
Does 33+66 look like 36+63?
NO
B.) 9(4 + 7) > 36 + 63
Does 36+63 look like 36+63?
YES
C.) 11(4 + 5) > 44 + 55
Does 44+55 look like 36+63?
NO
D.) 3(15 + 18) > 45 + 54
Does 45+54 look like 36+63?
NO
So...
The answer is: B.) 9(4 + 7)
Survive because your persevering through a tough time
