Answer:
It is composed of one phosphorus atom and four oxygen atoms covalently bonded together, and there is a –3 charge distributed over the entire ion.
Explanation:
The formula of phosphate ion is PO₄³⁻
The formula shows a phosphorus atom surrounded by 4 oxygen atoms.
For this bond to be established, phosphorus would be covalenty bonded to the oxygen atoms.
A covalent bond arises when two atoms with similar zero or very small electronegativity difference(≤ 0.5 ) combines. The electronegativity difference between phosphorus and oxygen is less than 0.5 and the two atom would bond by sharing of their electrons.
The net charge on the resulting radical is a -3 charge which it uses to form other bond types with other atoms. The charge implies an excess of 3 electrons on the radical formed.
Alkyl halide, Isobutylene
Explanation:
140.116 u ± 0.001 u is the answer
The square of the planet's orbital period is proportional to the cube of its semimajor axis.
Answer:
The order of solubility is AgBr < Ag₂CO₃ < AgCl
Explanation:
The solubility constant give us the molar solubilty of ionic compounds. In general for a compound AB the ksp will be given by:
Ksp = (A) (B) where A and B are the molar solubilities = s² (for compounds with 1:1 ratio).
It follows then that the higher the value of Ksp the greater solubilty of the compound if we are comparing compounds with the same ionic ratios:
Comparing AgBr: Ksp = 5.4 x 10⁻¹³ with AgCl: Ksp = 1.8 x 10⁻¹⁰, AgCl will be more soluble.
Comparing Ag2CO3: Ksp = 8.0 x 10⁻¹² with AgCl Ksp = AgCl: Ksp = 1.8 x 10⁻¹⁰ we have the complication of the ratio of ions 2:1 in Ag2CO3, so the answer is not obvious. But since we know that
Ag2CO3 ⇄ 2 Ag⁺ + CO₃²₋
Ksp Ag2CO3 = 2s x s = 2 s² = 8.0 x 10-12
s = 4 x 10⁻12 ∴ s= 2 x 10⁻⁶
And for AgCl
AgCl ⇄ Ag⁺ + Cl⁻
Ksp = s² = 1.8 x 10⁻¹⁰ ∴ s = √ 1.8 x 10⁻¹⁰ = 1.3 x 10⁻⁵
Therefore, AgCl is more soluble than Ag₂CO₃
The order of solubility is AgBr < Ag₂CO₃ < AgCl
