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kipiarov [429]
2 years ago
11

PLEASE ANSWER!!!!!!!! WILL MARK BRAILIEST

Chemistry
1 answer:
Mariana [72]2 years ago
6 0
9.Pubchem
10.Oxygen
11. Selenium fluoride
12. Disilicon Hexabromide
13. sulfur tetrachloride
14.Methane
15.diboron silicide
16. Nitrogen trifluoride

PLEASE GIVE ME BRAINLIEST!
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The formation of aluminum chloride can be described by the balanced chemical equation.
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Answer:this is hard tho-

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4 0
2 years ago
3. Your company makes 1000 boxes of 500 g baking soda per day.
inessss [21]

500,000 g of baking soda is present in 1000 boxes of 500 g baking soda boxes.

Answer:

Option C.

Explanation:

As 500 g of baking soda is taken in each box of that company. The total weight of baking soda in all the boxes can be determined by adding the weights of each box. This is possible only when the number of boxes is less. But if the number of boxes are large, then we can determine the total weight of baking soda by multiplying the number of boxes with the weight in each box.

So in this case, 1000 boxes are present and in that 500 g of baking soda are present in each box.

So total grams of baking soda will be 1000 * 500 = 5,00,000 g.

Thus, 500,000 g of baking soda is present in 1000 boxes of 500 g baking soda boxes.

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3 years ago
How much heat (in kj) is released when 3.600 mol naoh(s) is dissolved in water? (the molar heat of solution of naoh is â445.1 kj
Fantom [35]
<span>-1602 kj

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8 0
3 years ago
Read 2 more answers
Law of Conservation of Mass in terms of atoms
VARVARA [1.3K]

No atoms are lost or made during the chemical reaction so the total mass of the products is equal to the total mass of the reactants. In an atom, protons and neutrons contribute to the mass and since the number of them doesn’t change, the mass doesn’t either.

4 0
3 years ago
If the natural abundance of Ag-107 is 51.84% what is the abundance of Ag-109?
ASHA 777 [7]

Answer:

Explanation:

48.16%

Well, both abundances have to total 100% so is Ag-107 is 51.84%, then Ag-109 must be 100 – 51.84 = 48.16%.

Hope This Helps :)

4 0
3 years ago
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