The reaction ratio of hydrogen to the ammonia produced is 3:2 hence if 3 moles of hydrogen produce 2 moles of ammonia thus mathematically,
3moleH2=2mole NH3
5moleH2=?
Thus cross-multiplying
(5*2)/3= 3⅓ moles.
The empirical formula is SCl_2.
The <em>empirical formula</em> (EF) is the simplest whole-number ratio of atoms in a compound.
The ratio of atoms is the same as the ratio of moles.
So, our job is to calculate the <em>molar ratio </em>of S to Cl.
Assume that you have 100 g of sample.
Then it contains 31.14 g S and 68.86 g Cl.
<em>Step</em> 1. Calculate the <em>moles of each element</em>
Moles of S = 31.14 g S × (1 mol S/(32.06 g S) = 0.971 30 mol S
Moles of Cl = 68.86 g Cl × (1 mol Cl/35.45 g Cl) = 1.9425 mol Cl
<em>Step 2</em>. Calculate the <em>molar ratio</em> of each element
Divide each number by the smallest number of moles and round off to an integer
S:Cl = 0.971 30: 1.9425 = 1:1.9998 ≈ 1:2
<em>Step 3</em>: Write the <em>empirical formula</em>
EF = SCl_2
Sulfur - S-16
Electronic configuration:
1s2 2s2 2p6 3s2 3p4
Hope it helped!!
1.267 x 10 ^ 24 is the total number of atoms
Answer:
A
Explanation:
The iron corrodes so it oxidized
