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mart [117]
3 years ago
10

Mole fraction of the solute in a 1.00. What is the molal aqueous eqaution?

Chemistry
1 answer:
Troyanec [42]3 years ago
6 0
Mole fraction is expressed as the number of moles of solute over the total number of moles of solute and the number of moles of solvent. When expressed in molal, this is equal to number of moles of solute per liter solvent. If the mole fraction is 1.00, this means, all that is in the solution is solute. Hence the molal equivalent is 1.00 too
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Precipitation reactions always occur when two aqueous solutions are mixed (T/F)
Studentka2010 [4]

Answer: The given statement is false.

Explanation:

Precipitation reaction is defined as the chemical reaction in which two aqueous solution upon mixing together results in the formation of an insoluble solid.

For example, NaCl(aq) + AgNO_{3} \rightarrow NaNO_{3}(aq) + AgCl(s)

Here AgCl is present in solid state so, it is the precipitate.

But it is not necessarily true that two aqueous solutions will always result in the formation of a precipitate.

For example, NaCl(aq) + KNO_{3}(aq) \rightarrow KCl(aq) + NaNO_{3}(aq)

Hence, we can conclude that the statement precipitation reactions always occur when two aqueous solutions are mixed, is false.

7 0
3 years ago
Which of the following is an inorganic compound?
oksian1 [2.3K]

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8 0
3 years ago
The ideal gas heat capacity of nitrogen varies with temperature. It is given by:
hammer [34]

Answer:

A)  1059 J/mol

B)  17,920 J/mol

Explanation:

Given that:

Cp = 29.42 - (2.170*10^-3 ) T + (0.0582*10^-5 ) T2 + (1.305*10^-8 ) T3 – (0.823*10^-11) T4

R (constant) = 8.314

We know that:

C_p=C_v+R

We can determine C_v from above if we make C_v the subject of the formula as:

C_v=C_p-R

C_V = 29.42-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4-8.314

C_V = 21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4

A).

The formula for calculating change in internal energy is given as:

dU=C_vdT

If we integrate above data into the equation; it implies that:

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4\,) du

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 1059J/mol

Hence, the internal energy that must be added to nitrogen in order to increase its temperature from 450 to 500 K = 1059 J/mol.

B).

If we repeat part A for an initial temperature of 273 K and final temperature of 1073 K.

then T = 273 K & T2 = 1073 K

∴

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})273/1+(5.82*10^{-7})1073/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)

U2-U1= 17,920 J/mol

3 0
3 years ago
CAN SOMEONE HELP ME?!?! IM CONFUSED
Sati [7]

Answer: Solar winds have an influence all the way to about 160 AU from the Sun. About how many kilometers is that?

24,000,000,000 km

48,000,000,000 km

240,000,000,000 km

480,000,000,000 km

Explanation:

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3 years ago
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o-na [289]
Combustion means the burning of something. So in the given question, you could say, “In this question, combustion means the burning of methane”.
8 0
3 years ago
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