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il63 [147K]
2 years ago
12

2 3/4 divided by 3 =

Mathematics
1 answer:
grin007 [14]2 years ago
3 0
11/12.........................
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A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
Read 2 more answers
HELP ASAP LIKE RIGHT NOWWWW ITS A QUIZ
crimeas [40]

Answer x=30

Step-by-step explanation:

3 0
3 years ago
Solve by factoring:<br> 5t=t ^2
elena-14-01-66 [18.8K]

Answer:

t=0 and t=5

Step-by-step explanation:

5t = t^2

Subtract 5t from each side

5t-5t = t^2 -5t

0= t^2 -5t

Factor out a t

0= t(t-5)

Using the zero product property

t=0  and t-5 =0

t=0  and  t-5+5=0+5

t=0 and t=5

7 0
2 years ago
Select the proper order from least to greatest for 2⁄3 , 7⁄6 , 1⁄8 , 9⁄10 . A. 1⁄8 , 2⁄3 , 9⁄10 , 7⁄6 . B. 7⁄6 , 9⁄10 , 2⁄3 , 1⁄
drek231 [11]
Let's look at the one that is less than 1/2.
This would be 1/8, so that should go first. We can eliminate B and c.
7/6 is more than 1, so we can eliminate d.
So, A would be the answer.
6 0
3 years ago
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Which of the 4 options is a function?<br> Need help quick
mafiozo [28]

I believe the answer is B.

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