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SOVA2 [1]
3 years ago
9

A) (x + 7)(2x - 1)

Mathematics
2 answers:
goblinko [34]3 years ago
7 0

Answer:

A.) 2x^2 + 13x - 7

B.) 3x^2 - 11x - 20

C.) y^2 + 13y + 36

D.) b^2 - 15b + 36

Step-by-step explanation:

For all of these you want to multiply the first thingy (Ex. x) in the first parenthesis by the first in the second parenthesis (Ex. 2x) plus the first one in the first (Ex. x) times the second one in the second (Ex. -1) plus the second one in the first one (Ex. 7) times the first one in the second parenthesis (Ex. 2x)  plus the second one in the first parenthesis (Ex. 7) times the second one in the second (Ex. -1)

A.) (x + 7)(2x - 1) = (2x * x) + (-1 * x) + (7 * 2x) + (7 * -1) = 2x^2 -x + 14x - 7 = <em>2x^2 + 13x - 7</em>

B.) (3x + 4)(x - 5) = (3x * x) + (3x * -5) + (4 * x) + (4 * -5) = 3x^2 - 15x + 4x - 20 = <em>3x^2 - 11x - 20</em>

C.) (y + 9) (y + 4) = (y * y) + (4 * y) + (9 * y) + (9 * 4) = y^2 + 4y + 9y + 36 = <em>y^2 + 13y + 36</em>

D.) (b - 12)(b - 3) = (b * b) + (b * -3) + (-12 * b) + (-12 * -3) = b^2 - 3b - 12b + 36 = <em>b^2 - 15b + 36</em>

snow_tiger [21]3 years ago
3 0
A) 2x to the power of 2 +13x-7
B) 3x to the power of 2 -11x -20
C) y to the power of 2 + 13y+36
D) b to the power of 2 -15b + 36
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motikmotik

Answer:

The radius of the sphere is 6\ cm

Step-by-step explanation:

we know that

The volume of a sphere is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

V=288\pi\ cm^{3}

substitute and solve for r

288\pi=\frac{4}{3}\pi r^{3}

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288*3/4=r^{3}

r^{3}=216

r=6\ cm

7 0
3 years ago
Which expression is equivalent to 13(6x +3) −p
34kurt

Answer:

-p+78x+39

Step-by-step explanation:

5 0
2 years ago
Harry has a part-time job as a babysitter. The table below shows the amount of money Harry earned for different numbers of hours
Dimas [21]

Answer:

Part A- The 1st box is 96 and the second box is 10.

PartB-

Part C-

Step-by-step explanation:

<h2><u><em>Part A:</em></u></h2>

5x12=60

6x12=72

8x12=96

10x12=120

So the 1st box is 96 and the second box is 10.

<h2><u><em>Part B:</em></u></h2>

5     $50

6     $60

8     $80

I know this because Harry receives $10 per hour so you have to multiply the number of hours by $10.

<h2><em><u>Part C:</u></em></h2>

If Harry babysits for 5 hours, he would receive $60 but if he does yard work for 5 hours, he would receive $50. Harry would receive $10 more by babysitting than by doing yard work.

Hoped this helped.

4 0
3 years ago
In one day, a book store earned $199 in sales for 4 copies of a new cookbook and 5 copies of a new science fiction novel. On the
Marina86 [1]

Answer:

The cookbook costs $36 per copy while the science fiction costs $11 per copy

Step-by-step explanation:

Here in this question, we are interested in calculating the price of the cookbook and the price of the science fiction novel.

Since we do not know the price of each, we start by assigning variables to stand in for these unknown prices.

Let the price of the cookbook be $x , while the price of the science fiction be $y

Now, on the first day, 4 copies of the cookbook and 5 copies of the fiction;

mathematically that would be 4 * x and 5 * y

We add both and sum to be $199

Thus we have;

4x + 5y = 199 ••••••••••(i)

On the second day;

3 copies of cookbook 3 * x = 3x with 4 copies of science fiction 4 * y

Adding both yielded 152;

Thus, we have ;

3x + 4y = 152••••••••••(ii)

So we need to solve both equations simultaneously to get the values of x and y

4x + 5y = 199

3x + 4y = 152

Multiply equation i by 3 and equation ii by 4

3 * 4x + 5y = 199

4 * 3x + 4y = 152

12x + 15y = 597

12x + 16y = 608

Now, subtract multiplied equation ii from multiplied equation i

(12x-12x) + (15y-16y) = (597-608)

-y = -11

y = 11

To get x, simply substitute in any of the equations;

let’s use equation 1

4x + 5y = 199

4x + 5(11) = 199

4x + 55 = 199

4x = 199-55

4x = 144

x = 144/4

x = 36

8 0
3 years ago
Y=x+1 and y=-x-3 in graphing,Substitution,and elemination
marysya [2.9K]

\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\GRAPHING\ \text{(look at the picture)}\\\\y=x+1\\for\ x=0\to y=0+1=0\to(0,\ 1)\\for\ x=-1\to y=-1+1=0\to(-1,\ 0)\\\\y=-x-3\\for\ x=0\to y=-0-3=-3\to(0,\ -3)\\for\ x=-3\to y=-(-3)-3=0\to(-3,\ 0)\\\\Solution:\ (-2,\ -1)


SUBSTITUTION\\\\\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right\\\\\text{substitute}\ y=-x-3\ \text{to the first equation}\\\\-x-3=x+1\ \ \ \ |+3\\-x=x+4\ \ \ \ |-x\\-2x=4\ \ \ \ |:(-2)\\x=-2\\\\\text{substitute the value of x to the second equation}\\\\y=-(-2)-3=2-3=-1\\\\Solution:\ (-2,\ -1)


ELIMINATION\\\\\underline{+\left\{\begin{array}{ccc}y=x+1\\y=-x-3\end{array}\right}\ \ \ |\text{add both sides of the equations}\\.\ \ \ \ 2y=-2\ \ \ \ |:2\\.\ \ \ \ \ \ y=-1\\\\\text{put the value of y to the first equation}\\\\-1=x+1\ \ \ \ |-1\\x=-2\\\\Solution:\ (-2,\ -1)

5 0
3 years ago
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