We are given with the reaction HCOOH(g) →CO2(g) + H2 (g). According to Dalton's law, the total pressure of a vessel is equal to the sum of the partial pressure of the components inside it. In this case, we plot first the data ln (ratio partial pressure of HCOOH to total pressure) vs time. Partial pressure is the difference of pressure (from one point to another). In this case, the equation is ln P(HCCOH) = -0.0146t - 0.2281 where R² = 0.9923. K is equal to <span> -0.0146 s-1. When the total pressure is 291, ln P is -0.66938, thus the time is 30.23 seconds. The half life is ln(0.5)/k equal to 47.46 seconds.</span>
Answer:
What is the charge on the barium ion and what is the charge of the hydroxide ion.
Explanation:
To get the correct formula they have to add to zero over all.
Answer:
The DNA can be found in the cell's nucleus and beside the DNA in the nucleus, humans and other complex organisms also have a small amount of DNA in cell structures known as mitochondria.
Explanation:
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Answer:
See explanation and image attached
Explanation:
Aromatic hydrocarbons undergo electrophillic substitution. Usually, substituted benzene is more or less reactive to electrophillic substitution compared to unsubstituted benzene.
Substituents on the benzene ring tend to direct the incoming electrophile during electrophillic substititution. The presence of the -CH3 group on toluene directs the incoming Br electrophile to the ortho/para position.
Where the incoming electrphile E is Bromine, we can see that in the ortho/ para product, the electron pushing -CH3 stabilizes the resonance structure formed and increases electron density at the ortho/para position via resonance compared to the meta product as we can see from the image attached. Hence, the ortho and para products predominate over meta products.
Image credit: Chemistry steps
2 Ca₅(PO₄)₃F + 7 H₂SO₄ → 3 Ca(H₂PO₄)₂ + 7 CaSO₄ + 2 HF
Explanation:
To balance the chemical reaction the number and type of atoms entering the reaction have to be equal to the type and atoms leaving the reaction.
In our case we have:
10 Ca entering the reaction and 10 Ca leaving the reaction
6 PO₄ groups entering the reaction and 6 PO₄ groups leaving the reaction
2 F entering the reaction and 2 F leaving the reaction
7 SO₄ groups entering the reaction and 7 SO₄ groups leaving the reaction
14 H entering the reaction and 14 H leaving the reaction
Learn more about:
balancing chemical equations
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