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Ivahew [28]
3 years ago
6

HELP IT’S ABOUT TO BE DUE!

Chemistry
1 answer:
Vinil7 [7]3 years ago
7 0
The answer is b
Explanation:
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How long will it take to deposit 6.32 g of copper from a CuSO4(aq) solution using a current of 0.554 amps
rjkz [21]

Answer:

34672.96 s

Explanation:

m = Mass of copper = 6.32 g

M = Molar mass of copper = 63.5 g/mol

F = Faraday constant = 96500 C/mol

The electrode equation would be

Cu^{2+}(aq)+2e^{-}=Cu(s)

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t = Time taken

Charge would be

Q=\dfrac{m}{M}eF\\\RightarrowQ=\dfrac{6.32}{63.5}\times 2\times 96500\\\Rightarrow Q=19208.82\ \text{C}

Charge is given by

Q=It\\\Rightarrow t=\dfrac{Q}{I}\\\Rightarrow t=\dfrac{19208.82}{0.554}\\\Rightarrow t=34672.96\ \text{s}

Time taken to deposit the copper is 34672.96 s.

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