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Snowcat [4.5K]
3 years ago
5

Write a balanced net ionic equation for the reaction between K3PO4 (aq) (potassium phosphate) and Fe(NO3)2 (aq) (iron (II) nitra

te)
Chemistry
1 answer:
sertanlavr [38]3 years ago
3 0

<u>Answer:</u> The net ionic equation is given below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium nitrate and sodium hydroxide is given as:

2K_3PO_4(aq.)+3Fe(NO_3)_2(aq.)\rightarrow Fe_3(PO_4)_2(s)+6KNO_3(aq.)

Ionic form of the above equation follows:

6K^+(aq.)+2PO_4^{3-}(aq.)+3Fe^{2+}(aq.)+6NO_3^-(aq.)\rightarrow Fe_3(PO_4)_2(s)+6K^+(aq.)+6NO_3^-(aq.)

As, potassium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

2PO_4^{3-}(aq.)+3Fe^{2+}(aq.)\rightarrow Fe_3(PO_4)_2(s)

Hence, the net ionic equation is given above.

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A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution
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Answer:

0.136g

Explanation:

A student dissolved 5.00 g of Co(NO3)2 in enough water to make 100. mL of stock solution. He took 4.00 mL of the stock solution and then diluted it with water to give 275. mL of a final solution. How many grams of NO3- ion are there in the final solution?

Co(NO_3)_2(aq)\rightarrow Co^{2+}(aq)+2NO_3^{-}(aq)

Initial mole of Co(NO3)2  =\frac{mass}{molar mass}

=\frac{5.00}{182.94} \\\\=0.02733mol

Mole of Co(NO3)2 in final solution

=\frac{4.00}{100}\times 0.02733\\\\=0.04\times 0.02733\\\\= 0.001093mol

Mole of  NO3- in final solution = 2 x Mole of Co(NO3)2

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6 0
4 years ago
Consider the following reaction.
Ivan

Answer:

162 g Fe₂O₃

Explanation:

To find the mass of Fe₂O₃, you need to (1) convert grams C to moles C (via molar mass from periodic table), then (2) convert moles C to moles Fe₂O₃ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles Fe₂O₃ to grams (via molar mass). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the given value.

Molar Mass (C): 12.011 g/mol

2 Fe₂O₃(s) + 3 C(s) ---> 4 Fe(s) + 3 CO₂(g)

Molar Mass (Fe₂O₃): 2(55.845 g/mol) + 3(15.998 g/mol)

Molar Mass (Fe₂O₃): 159.684 g/mol

18.3 g C           1 mole            2 moles Fe₂O₃          159.684 g
--------------  x  ----------------  x  -------------------------  x  -----------------  = 162 g Fe₂O₃
                        12.011 g              3 moles C                 1 mole

5 0
2 years ago
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Answer:

B. 5 \times  {10}^{ - 5}\: m

Explanation:

0.00005  \: m= 5 \times  {10}^{ - 5} \: m  \\

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