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Snowcat [4.5K]
3 years ago
5

Write a balanced net ionic equation for the reaction between K3PO4 (aq) (potassium phosphate) and Fe(NO3)2 (aq) (iron (II) nitra

te)
Chemistry
1 answer:
sertanlavr [38]3 years ago
3 0

<u>Answer:</u> The net ionic equation is given below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium nitrate and sodium hydroxide is given as:

2K_3PO_4(aq.)+3Fe(NO_3)_2(aq.)\rightarrow Fe_3(PO_4)_2(s)+6KNO_3(aq.)

Ionic form of the above equation follows:

6K^+(aq.)+2PO_4^{3-}(aq.)+3Fe^{2+}(aq.)+6NO_3^-(aq.)\rightarrow Fe_3(PO_4)_2(s)+6K^+(aq.)+6NO_3^-(aq.)

As, potassium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

2PO_4^{3-}(aq.)+3Fe^{2+}(aq.)\rightarrow Fe_3(PO_4)_2(s)

Hence, the net ionic equation is given above.

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Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

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The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

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This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

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m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

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