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3 years ago

What might happen to the sickle-cell mutation if malaria in Africa were eliminated?

Chemistry

1 answer:

vichka [17]3 years ago

4 0

Explanation:

The allele for sickle cell would gradually be eliminated from the populations over generations. This is because while initially natural selection favoured and fitted the allele in the environment because its bearers are less vulnerable to malaria, sickle cells also result in reduced capacity of the red blood cells to carry oxygen to tissues. Therefore in the absence of Malaria, sickle cell would thereby offer a disadvantage to an individual hence be eliminated by natural selection.

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Under which conditions of temperature and pressure does a real gas behave most like an ideal gas

castortr0y [4]

Answer:

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure, as the potential energy due to intermolecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them.

Explanation:

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3 years ago

Compare the reactivity of magnesium and calcium explain the difference

dem82 [27]

Answer:

Calcium is more reactive than magnesium because calcium atom is larger than magnesium atom and it has one more energy level. ... Thus Ca is more reactive than Mg.

6 0

3 years ago

The diagram to the right is composed of carbon hydrogen and oxygen so is an example of a

Liono4ka [1.6K]

Carbohydrates. If you think about it, it's a mix of the three words.

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4 years ago

The process of an atom releasing energy when it moves to a lower energy state is called

Inga [223]

The process of an atom releasing energy when it moves to a lower energy state is called emission.

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3 years ago

if the mass of 191 grams NaCl reacted with 74 frams of calcium hydroxide and 80 grams of sodium hydroxide is produced, what mass

nadya68 [22]

<h3>Answer:</h3>

110.98 g/mol

<h3>Explanation:</h3>

The reaction between NaCl and Ca(OH)₂ is given by the equation;

2NaCl(aq) + Ca(OH)₂(s) → 2NaOH(aq) + CaCl₂(aq)

We are required to determine the mass of CaCl₂ produced,

We will use the following simple steps;

Step 1: Moles of NaCl and Ca(OH)₂ given

Number of moles = Mass ÷ Molar mass

Moles of NaCl

Mass of NaCl = 191 g

Molar mass NaCl = 58.44 g/mol

Number of moles = 191 g ÷ 58.44 g/mol

= 3.268 moles

= 3.27 Moles

Moles of Ca(OH)₂

Mass of Ca(OH)₂ = 74 g

Molar mass of Ca(OH)₂ = 74.093 g/mol

Number of moles = 74 g ÷ 74.093 g/mol

= 0.998 mole

= 1.0 mole

However, from the equation 2 moles of NaCl requires 1 mole of Ca(OH)₂

Therefore, from the amount of reactants available NaCl was in excess and Ca(OH)₂ is the limiting reactant .

Step 2: Moles of CaCl₂ produced

From the equation

1 mole of Ca(OH)₂ reacts with NaCl to produce 1 mole of CaCl₂

Therefore; the mole ratio of Ca(OH)₂ to CaCl₂ is 1: 1

Thus;

Moles of CaCl₂ produced is 1.0 moles

Step 3: Mass of CaCl₂ produced

Moles of CaCl₂ = 1.0 mole

Molar mass CaCl₂ = 110.98 g/mol

But; mass = number of moles × Molar mass

Therefore;

Mass of CaCl₂ = 1.0 mole × 110.98 g/mol

= 110.98 g CaCl₂

3 0

3 years ago