Divide the number of events by the number of possible outcomes. This will give us the probability of a single event occurring. In the case of rolling a 3 on a die, the number of events is 1 (there's only a single 3 on each die), and the number of outcomes is 6.
it would be 2/6 bc, one die, rolled twice, and landing on a 2 the first time and 6 the second time, is actually a 2/6 chance, you have 6 numbers, one die, two chances.
There are no such numbers in real numbers.
Do you perhaps want a solution in complex numbers?
Answer:
3
Step-by-step explanation:
All factorials 5 and above are evenly divisible by 15, so have no remainder. Thus, you are interested in ...
mod(1! +2! +3! +4!, 15) = mod(1 +2 +6 +24, 15)
= mod(33, 15) = 3
The remainder is 3.
40.9267 is the square root
