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3 years ago

Help me please!!!!!!!

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

3 0

Answer:

I have no idea.

Step-by-step explanation:

I failed geometry.

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Candice buys a board thats is 12 feet long. the store incorrectly measures and prices the board at 13.2 feet. whats the percent

podryga [215]

Determine first the difference between the incorrectly measured board and the correct one. The subtraction would result to 1.2 ft. The percent error is calculated by dividing this value by the correct value and then multiply by 100%. (1.2 ft / 12 ft) x 100% = 100%. Thus, the percent error is 10%.

7 0

3 years ago

Read 2 more answers

Don't have time for any bs please answer the question or don't do it at all

Serhud [2]

Answer:

1.) (11, -7/3), 2.) No solution. 3.) (1, 3)

Step-by-step explanation:

1.)

2x + 3y = 15

x - 3y = 18

Solve...use elimination method

2x + x + 3y - 3y = 15 + 18

3x = 33

x =11

11 - 3y = 18

-3y = 7

y = -7/3

(11, -7/3)

---------------------------------------

2.) y = 4x + 4

y = 4x - 4

Use substitution.

4x + 4 = 4x - 4

4 = -4 FALSE NO Solution

3.) y = 5- 2x

4x + 3y = 13

Can use elimination method

2y = 10 - 4x

add it to 4x + 3y = 13

10 + 3y = 2y + 13

y = 3

3 = 5 - 2x

x = 1

(1, 3)

5 0

3 years ago

A cable car starts off with n riders. The times between successive stops of the car are independent exponential random variables

nikitadnepr [17]

Answer:

The distribution is $\frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}$

Solution:

As per the question:

Total no. of riders = n

Now, suppose the $T_{i}$ is the time between the departure of the rider i - 1 and i from the cable car.

where

$T_{i}$ = independent exponential random variable whose rate is $\lambda$

The general form is given by:

$T_{i} = \lambda e^{- lambda}$

(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:

$S_{n} = T_{1} + T_{2} + ........ + T_{n}$

$S_{n} = \sum_{i}^{n} T_{n}$

Now, the sum of the exponential random variable with $\lambda$ with rate $\lambda$ is given by:

$S_{n} = f(t:n, \lamda) = \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}$

5 0

3 years ago

What is the simplified form of the following expression? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0 2

finlep [7]

To solve such questions we need to know more about expression.

<h2 /><h2>Expression </h2>

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations that are formed according to rules which are dependent on the context.

<h2 /><h2 /><h2>Given to us,</h2>

$2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-4\sqrt[4]{32y}+5\sqrt[4]{x}-16\sqrt[4]{2y}+13\sqrt[4]{4}-10\sqrt[4]{2y}+35\sqrt[4]{x}-18\sqrt[4]{2y}$

rearranging we get,

$=2\sqrt[4]{16x}+3\sqrt[4]{81x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{4}+35\sqrt[4]{x}-2\sqrt[4]{2y}-4\sqrt[4]{32y}-4\sqrt[4]{32y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$

we know that,

$\sqrt[4]{81}=3\\\sqrt[4]{16}=2\\\sqrt[4]{32}=2\sqrt[4]{2}\\$

therefore,

$=4\sqrt[4]{x}+9\sqrt[4]{x}+5\sqrt[4]{x}+5\sqrt[4]{x}+13\sqrt[4]{x}+35\sqrt[4]{x}-2\sqrt[4]{2y}-8\sqrt[4]{2y}-8\sqrt[4]{2y}-16\sqrt[4]{2y}-10\sqrt[4]{2y}-18\sqrt[4]{2y}$