Answer:
u = 0.176 m/x
Explanation:
∴ n O2 = 1 mol
∴ mass O2 = 1 mol * 32 g/mol = 32 g
∴ T = 60°C = 333 K
∴ P = 5 bar
⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)
⇒ V = 5537.124 cm³
∴ d = 20cm
⇒ A = (1/4π)*d² = 314.16 cm²
velocity of the gas (m/x):
- u = m / ρ*A
- let time (t) = x sec
∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³
∴ mass flow rate (m) = 32g / x
⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))
⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x
Answer:
A dono wat is da anser sori man hehe
Answer:
To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).
Now, to obtain 29 percent of 603.27, we must make the following calculation: 603.27 / 100 x 29, which gives a total of 174.94 grams.
In this way, your reasoning is correct and it is probably a mistake in the book.
Answer:
1. Fe(NO3)3 is C. Chemical formula
2. Manganese Sulphate is C. Name
3. Zn is C. Symbol
Hope this helps!
Answer:
Calcium (Ca) => 2
Aluminium (Al) => 3
Rubidium (Rb) => 2
Oxygen (O) => 2
Sulphur (S) => 2
Iodine (I) => 1
<em><u>Formulae</u></em>
<em>Calcium</em><em> </em><em>oxide</em><em> </em><em>:</em><em> </em>CaO
<em>Alumin</em><em>ium</em><em> </em><em>iodide</em><em> </em><em>:</em><em> </em>AlI3
<em>Rubidi</em><em>um</em><em> </em><em>sulphide</em><em> </em><em>:</em><em> </em>RbS
<em>Alum</em><em>inium</em><em> </em><em>oxide</em><em> </em><em>:</em><em> </em>Al2O3