Answer:
During the year 2021.
Step-by-step explanation:
As we have a function that defines the annual per capita out-of-pocket expenses for health care, we can work with it.
Knowing that, <u>we clear x</u> (<em>this is the number of years past the year 2000, so it will contain our desired information</em>).
Now, as we want to know when are the per capita out-of-pocket expenses for health care predicted to be $1400, and <em>this total is our variable y</em>, then
Finally, we know that <u>x is the number of years past the year 2000</u>, so the answer is that during the year 2021, <em>the per capita out-of-pocket expenses for health care are predicted to be $1400</em>.
Answer:
The chances that the dice will not land on 6 is 5/6.
Answer:
The two linear equation
x + y = 19.... Equation 1
0.55x + 0.75y = 12.65... Equation 2
Nedra purchased
9 Apples and 11 Oranges
Step-by-step explanation:
Nedra purchased apples and oranges at the grocery store. which two linear equations can be used to find the number of apples and oranges?
Let the number of apples be represented by x
The number of oranges by represented by y.
Hence,
Apples are $0.55 each and oranges are $0.75 each. If she spent a total of $12.65 for 19 pieces of fruit,
Hence:
x + y = 19..... Equation 1
x = 19 - y
$0.55 × x + $0.75 × y = $12.65
0.55x + 0.75y = 12.65.....Equation 2
Hence: we substitute 19 - y for x in Equation 2
0.55(19 - y) + 0.75y = 12.65
10.45 - 0.55y + 0.75y = 12.65
-0.55y+ 0.75y = 12.65 - 10.45
0.20y = 2.2
y = 2.2/0.20
y = 11 oranges
x = 19 - y
x = 19 - 11
x = 8 Apples
Answer:
14
First multiply
1 and 3/4 by 8 and then you got your answer
Hello from MrBillDoesMath!
Answer:
See Discussion below
Discussion:
(sinq + cosq)^2 = => (a +b)^2 = a^2 + 2ab + b^2
(sinq)^2 + (cosq)^2 + 2 sinq* cosq => as (sinx)^2 + (cosx)^2 = 1
1 + 2 sinq*cosq (*)
Setting a = b = q in the trig identity:
sin(a+b) = sina*cosb + cosa*sinb
sin(2q) = (**)
sinq*cosq + cosq*sinq => as both terms are identical
2 sinq*cosq
Combining (*) and (**)
(sinq + cosq)^2 = 1 + 2sinq*cosq => (**) 2sinq*cosq = sqin(2q)
= 1 + sin(2q)
Hence
(sinq + cosq)^2 = 1 + sin(2q) => subtracting 1 from both sides
(sinq + cosq)^2 - 1 = sin(2q)
The last statement is what we are trying to prove.
Thank you,
MrB
