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2 years ago

Find the area of the composite figure 10 ft 4 ft 3 ft 6 ft square feet

Mathematics

2 answers:

mina [271]2 years ago

8 0

Answer:

Exercise Problem Solution

1 Find the perimeter of a triangle the sides of which are 10 in, 14 in and 15 in. P = 10 in + 14 in + 15 in = 39 in

2 A rectangle has a length of 12 cm and a width of 4 cm. Find its perimeter. P = 12 cm + 12 cm + 4 cm + 4 cm = 32 cm

3 Find the perimeter of a regular hexagon with each side measuring 8 m. P = 6(8 m) = 48 m

4 The perimeter of a square is 20 ft. How long is one side? 20 ft ÷ 4 = 5 ft

5 The perimeter of a regular pentagon is 100 cm. How long is one side? 100 cm ÷ 5 = 20 cm

Step-by-step explanation:

irina [24]2 years ago

6 0

Answer:

61 square feet

Step-by-step explanation:

Your rectangle has a area of A = w l

A = 4*10 = 40

The triangle has a area of A = h (b/2)

A = 7 (6/2)

A = 21

Add both for the area

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2 years ago

6,666,666×666,666 /1+2+3+4+5+6+5+4+3+2+1 − 777,777×777,777/1+2+3+4+5+6+7+6+5+4+3+2+1

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Answer:

111111 $\times$ 1111110 is the simple expression.

Step-by-step explanation:

The expression to be solved:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1} - \dfrac{777,777\times777,777}{1+2+3+4+5+6+7+6+5+4+3+2+1}$

First of all, let us solve the first term:

$\dfrac{6,666,666\times666,666 }{1+2+3+4+5+6+5+4+3+2+1}\\\Rightarrow \dfrac{6666666\times666666 }{36}\\\Rightarrow \dfrac{6666666\times666666 }{6\times 6}\\\Rightarrow 1111111\times 111111$

Now, the right term:

$\dfrac{777777\times777777}{1+2+3+4+5+6+7+6+5+4+3+2+1}\\\Rightarrow \dfrac{777777\times777777}{49}\\\Rightarrow \dfrac{777777\times777777}{7 \times 7}\\\Rightarrow 111111 \times 111111$

So, the expression to be solved becomes:

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Answer:

Step-by-step explanation:

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