Question

Find the perimeter of the triangle in units. Round to two decimal places as necessary.

Answer 1

Answer:

• 54.56 units

Step-by-step explanation:

The vertices are:

• K(-12,2), L(-7,12), J(3,-10)

Find the sides using distance formula:

• KL = $\sqrt{(-7+12)^2+(12-2)^2} = \sqrt{125}$ ≈ 11.18
• LJ = $\sqrt{(3+7)^2+(-10-12)^2} = \sqrt{584}$ ≈ 24.17
• KJ = $\sqrt{(3+12)^2+(-10-2)^2} = \sqrt{369}$ ≈ 19.21

Find perimeter:

• P = KL + LJ + KJ
• P = 11.18 + 24.17 + 19.21 = 54.56 units