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mojhsa [17]
2 years ago
13

In rectangle ABCD, AB = 10 cm and BC = 14 cm. If rectangle EFGH is the image after a dilation, which could be its side lengths?

Mathematics
1 answer:
kakasveta [241]2 years ago
3 0

Answer:

EF = 25 cm and FG = 35 cm

Step-by-step explanation:

After finding each scale factor for each of the 4 answers, only the last option is relatable. Every other option resulted in different numbers of EF and FG.

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For all values of x,
Nana76 [90]

Answer:

For f(x) = 2x + 3 and g(x) = -x 2 + 1, find the composite function defined by (f o g)(x)

(f o g)(x) = f(g(x))

= 2 (g(x)) + 3

= 2( -x 2 + 1 ) + 3

= - 2 x 2 + 5 Given f(2) = 3, g(3) = 2, f(3) = 4 and g(2) = 5, evaluate (f o g)(3)

Step-by-step explanation:

6 0
2 years ago
What is the MAD of this numbers?
Stella [2.4K]
We know that
The MAD is <span>the mean absolute deviation of the data

step 1
</span><span>To find the mean absolute deviation of the data, start by finding the mean of the data set.
</span><span>Find the sum of the data values, and divide the sum by the number of data values
</span>sum of the data values=[130+150+190+100+175+120+165+140+180+190]
sum of the data values=1540
number of data=10
Mean=1540/10-----> 154

step 2
<span>Find the absolute value of the difference between each data value and the mean: |data value – mean|.
</span> |130 – 154|=24
 |150 – 154|=4
 |190 – 154|=44
 |100 – 154|=54
 |175 – 154|=21
 |120 – 154|=34
 |165 – 154|=11
 |140 – 154|=14
 |180 – 154|=26
 |190 – 154|=44

step 3
<span>Find the sum of the absolute values of the differences.
</span>=[24+4+44+54+21+34+11+14+26+44]------> 276

step 4
<span>Divide the sum of the absolute values of the differences by the number of data values.
</span>276/10-----> 27.6

the answer is
27.6
5 0
3 years ago
Find the values of x and y that makes each equation true. –(5y)i+12=4x+25i
vovikov84 [41]

Equate real part and imaginary part:

LHS:

real part -- 12

imaginary part -- 5y

RHS:

real part = 4x

imaginary part = 25

Equating::

12 = 4x

x = 12/4

x = 3

Again:

5y = 25

y = 25/5

y = 5

So,

x = 3

y = 5

5 0
1 year ago
Need help what is the answer and what is the equation
My name is Ann [436]
10 degrees Celsius is 50 degrees Fahrenheit. 
The equation for C to F is below. 
C(9/5)+32= F
Multiply C by 1.8 (or 9/5) then add 32.
10(9/5)+32= 50 F
5 0
3 years ago
In a survey of 1,003 adults concerning complaints about restaurants, 732 complained about dirty or ill-equipped bathrooms and 38
Ganezh [65]

Answer:

a

0.716  <  p <  0.744

b

0.3498  <  p <  0.4089

c

 With the result obtained from a and b the manager can be 95 % confidence that the proportion of the population that complained about dirty or ill-equipped bathrooms are within the interval obtained at  a

and that

the proportion of the population that complained about loud or distracting diners at other tables are within the interval obtained at  b

Step-by-step explanation:

From the question we are told that

The sample size is  n  =  1003

The number that complained about dirty or ill-equipped bathrooms is e = 732

 The number that complained about loud or distracting diners at other tables is  q =  381

Given that the the confidence level is  95% then the level of significance is mathematically represented as  

         \alpha = (100- 95)\%

         \alpha = 0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table , the value is  

         Z_{\frac{\alpha }{2} } =  1.96

Considering question a

The sample proportion is mathematically represented as

           \r p  =  \frac{e}{n}

=>        \r p  =  \frac{732}{1003}

=>        \r p  =  0.73

Generally the margin of error is mathematically represented as

          E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{ \r p (1- \r p)}{n} }

          E =  1.96*  \sqrt{ \frac{ 0.73 (1- 0.73)}{1003} }

          E = 0.01402

The 95% confidence interval is  

        \r p  -  E  <  p  <  \r p +E

        0.73 - 0.01402 <  p <  0.73 +  0.01402

        0.716  <  p <  0.744

Considering question b

The sample proportion is mathematically represented as

           \r p  =  \frac{q}{n}

=>        \r p  =  \frac{381}{1003}

=>        \r p  =  0.3799

Generally the margin of error is mathematically represented as

          E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{ \r p (1- \r p)}{n} }

          E =  1.96*  \sqrt{ \frac{ 0.3799 (1- 0.3799)}{1003} }

          E = 0.0300

The 95% confidence interval is  

        \r p  -  E  <  p  <  \r p +E

        0.3798 - 0.0300 <  p <  0.3798 + 0.0300

        0.3498  <  p <  0.4089

8 0
3 years ago
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