Question

Please help me please

Answer 1

The key to this problem is to write out the probabilities and determine which one is most likely and least likely (or impossible).

Drawing a black card from a standard deck of playing cards:

There are 52 cards in a playing deck, 26 are red and 26 are black.

$\frac{26}{52}$ = $\frac{1}{2}$

A spinner has 5 equal sections numbered 1 through 5. You spin and land on a number less than or equal to 4.

This means that all the numbers (1, 2, 3, and 4) except 5.

$\frac{4}{5}$

You roll a standard number cube and get a number less than 2.

A standard cube is from 1 to 6, and 1 is the only number on the cube that is less than 2.

$\frac{1}{6}$

You roll two standard number cubes and the sum is 1.

The smallest number on a standard cube is 1, so you can't make the sum 1 with 2 dice.

0

If we put these in order, we get:

$\frac{4}{5}$, $\frac{1}{2}$, $\frac{1}{6}$, 0

So, the order going from top to bottom in the picture is: 2, 1, 3, 4