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3 years ago

For a sample variance of n = 36 that has a sample variance of 1,296, what is the estimated error for the sample?

Mathematics

1 answer:

lukranit [14]3 years ago

7 0

Answer:

Step-by-step explanation:

Given :

Sample size, n = 36

Sample variance, s² = 1296

The estimated standard error can be obtained using the relation :

Standard Error, S. E = standard deviation / √n

Standard deviation, s = √1296 = 36

S.E = 36/√36

S.E = 36/6

S.E = 6

Hence, estimated standard error = 6

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A sociologist records the annual household income (in thousands of dollars) among a sample of families living in a high-crime ne

Gnoma [55]

Answer:

The lower quartile is $Q_1=33$ thousand dollars.

The median quartile is $Q_2=39$ thousand dollars.

The upper quartile is $Q_3=45$ thousand dollars.

Step-by-step explanation:

The lower quartile is the median value of the lower half of a data set at the 25th percentile of a distribution.

The median quartile is the median value of a data set at the 50th percentile of a distribution.

The upper quartile is the median value of the upper half of a data set at the 75th percentile of a distribution.

To locate each quartile in a data set, we follow four steps:

Step 1: Put the numbers in order: 23, 25, 33, 34, 39, 39, 44, 45, 48, 55

Step 2: The median is given by $\frac{n+1}{2}$ where n is all scores in the data set.

Because n = 10, the median position is $\frac{10+1}{2}=5.5$

The median is the average of the fifth and sixth positioned scores

$Q_2=\frac{39+39}{2} =39$

Step 3: Compute $\frac{n+1}{2}$ where n is all scores below $Q_2$ .

For scores below $Q_2$ , use only 23, 25, 33, 34, 39.

Because n = 5, the median position is $\frac{5+1}{2}=3$

The median is the third positioned score: $Q_1=33$

Step 4: Compute $\frac{n+1}{2}$ where n is all scores above $Q_2$ .

For scores above $Q_2$ , use only 39, 44, 45, 48, 55

Because n = 5, the median position is $\frac{5+1}{2}=3$

The median is the third positioned score: $Q_3=45$

7 0

3 years ago

3x + (x-8) = 23 how do I solve it

Ostrovityanka [42]

<span>3x + (x-8) = 23

Combine like terms first. You can combine 3x and x because they have the same variable.

4x - 8 = 23
Now add 8 to both sides.
4x = 31

Last step is to divide both sides by 4 to isolate the x.
4/4x = 31/4

x = 7.75 is the answer.</span>

4 0

3 years ago

Paul opens a savings account with $350. He saves $150 per month. Assume that he does not withdraw money or make any additional d

Verizon [17]

I believe the equation is y=350+150x with y being the total amount of money in his account and x being the number of months..Paul starts with $350, which is the y-intercept (starting value) of the equation then the slope is 150 because his total savings increases by $150 for every month he saves without making any withdrawals. I apologize if I'm wrong but I hope this helps.

8 0

3 years ago

Which equation represents the polynomial function with zeros −1, 1, and 3 (multiplicity of 2), and a y-intercept of −18? (4 poin

Vlad [161]

Correct Answer:
3rd option is the correct answer

Solution:
The zeros of the polynomial are -1,1 and 3. The multiplicity of 3 is 2. So the polynomial can be expressed as:

$y=a (x-3)^{2}(x-1)(x+1)$

The y-intercept of the polynomial is -18. This means the polynomial passes through the point (0,-18). Therefore, y must be -18 when x = 0. Using these values of x and y in previous equation we get:

$-18=a (0-3)^{2}(0-1)(0+1) \\ \\ 
-18=-9a \\ \\ 
a=2$

The final equation of the polynomial becomes:

$y=2 (x-3)^{2}(x-1)(x+1)$

7 0

3 years ago

Here are the equations for 4

Kipish [7]

Answer:

Please see attached graph.

Step-by-step explanation:

The equations for straight lines are given as:

i) y = x +4

ii) y= x-4

Yon can form a table for values of x and y that are true for an equation and use these values as coordinates ( x,y ) to plot the graphs and view the lines to select the correct labels for the equations.

For i)

y= x+4

x y coordinates

-3 1 (-3,1 )

-2 2 (-2,2)

-1 3 (-1,3)

0 4 ( 0,4)

1 5 ( 1,5)

2 6 ( 2,6)

3 7 ( 3,7)

Plot the points on a graph tool and draw the line. Do the same for the second equation to view both graphs as shown in the attached graph.

6 0

3 years ago