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LuckyWell [14K]
2 years ago
6

I don’t know what this is I took a picture of it here.

Mathematics
1 answer:
IRISSAK [1]2 years ago
4 0
Function a: exponential function
Function b: linear function
Function c: exponential function
You might be interested in
Write two different rational functions whose graphs have the same end behaviour as the graph of y=3x^2
baherus [9]

Answer:

               y=x^2+5x+20\\ \\ y=8x^2+35

Explanation:

The <em>end behavior</em> of a <em>rational function</em> is the limit of the function as x approaches negative infinity and infinity.

Note that the the values of even functions are the same for ± x. That implies that their limits for ± ∞ are equal.

The limits of the quadratic function of general form y=ax^2+bx+c as x approaches negative infinity or infinity, when a  is positive, are infinity.

That is because as the absolute value of x gets bigger y becomes bigger too.

In mathematical symbols, that is:

\lim_{x \to -\infty}3x^2=\infty\\ \\ \lim_{x \to \infty}3x^2=\infty

Hence, the graphs of any quadratic function with positive coefficient of the quadratic term will have the same end behavior as the graph of y = 3x².

Two examples are:

         y=x^2+5x+20\\ \\ y=8x^2+35

5 0
3 years ago
A box contain 12 balls in which 4 are white 3 are blue and 5 are red.3 balls are drawn at random from the box.find the chance th
Anastasy [175]

Answer:

3/11

Step-by-step explanation:

From the above question, we have the following information

Total number of balls = 12

Number of white balls = 4

Number of blue balls = 3

Number of red balls = 5

We solve this question using combination formula

C(n, r) = nCr = n!/r!(n - r)!

We are told that 3 balls are drawn out at random.

The chance/probability of drawing out 3 balls = 12C3 = 12!/3! × (12 - 3)! = 12!/3! × 9!

= 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1/(3 × 2 × 1) × (9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1)

= 220 ways

The chance of selecting 3 balls at random = 220

To find the chance that all the three balls are selected,

= [Chance of selecting (white ball) × Chance of selecting(blue ball) × Chance of selecting(red balls)]/ The chance/probability of drawing out 3 balls

Chance of selecting (white ball)= 4C1

Chance of selecting(blue ball) = 3C1 Chance of selecting(red balls) = 5C1

Hence,

= [4C1 × 3C1 × 5C1]/ 220

= 60/220

= 6/22

= 3/11

The chance that all three are selected is = 3/11

4 0
3 years ago
Find the volume of the cylinder. Give you answers both in terms of π and rounded to the nearest tenth.
Ugo [173]

Answer:

Step-by-step explanation:

The formula for determining the volume of a cylinder is expressed as

Volume = πr²h

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

Height = 19 cm

Since the base area is 24π cm², we would determine its radius by applying the formula,

Area of circle = πr²

24π = πr²

r² = 24

r = √24

Therefore,

Volume of cylinder = π × (√24)² × 19 = 456π cm³

It is approximately

456 × 3.14 = 1431.8 cm³

3 0
2 years ago
It's Mean Median Mode Range
Rufina [12.5K]

Answer:

I believe the median is 21

hope this helps

4 0
3 years ago
Read 2 more answers
Solve the equation -3(x - 14) + 9x = 6x + 24. Does the equation have
Black_prince [1.1K]
-3(x-14)+9x=6x+24
-3x+42+9x=6x+24
-3x+9x-6x=-24-42
0=-18
6 0
3 years ago
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