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aleksandr82 [10.1K]
3 years ago
9

HOW MANY LANGUAGES CAN YOU SPEAK​

Mathematics
1 answer:
solniwko [45]3 years ago
6 0

Answer:Yo puedo hablar español and i can speak english and Также я могу говорить по русски=i can also speak russian

Step-by-step explanation:

You might be interested in
can anyone's please explain how you got this answer with explanation....(if nonsense answers I will report)​
solong [7]

Answer:

12.5%

Step-by-step explanation:

45/360×100=12.5

8 0
3 years ago
Solve for n. 2/3(1 + n) = - 1/2n
alexandr1967 [171]

Answer:

⅔+⅔n=-½

6×⅔+6×⅔n=6×-½

2×2+2×2n=-3

4+4n=-3

4n=-3-4

4n=-7

n=-7/4

8 0
3 years ago
DUPLICATE. WITH ATTACHMENTS
Inessa05 [86]
7.) Area of a square pyramid is given by A = s^2 + 2sl; where s is the side length of the base and l is the slant height.
Area of given pyramid = 4^2 + (2 x 4 x 7) = 16 + 56 = 72 ft^2

8.) Area of the given pyramid is the area of the hexagonal base plus the area of the six slant triangles.
Area of hexagonal base = (3sqrt(3))/2 x 10^2 = 150 x 1.732 = 259.8
Area of the 6 traingles = 6(1/2 x 10 x 13) = 6 x 65 = 390
Total surface area of the pyramid = 259.8 + 390 = 649.8 ≈ 650 m^2

9.) Using pythagoras rule, the slant height is sqrt(6^2 + 3.5^2) = sqrt(36 + 12.25) = sqrt(48.25) = 6.9 mm

10.) The surface area of a cone is given by πr^2 + πrl
Area = π x 6^2 + π x 6 x 20 = 36π + 120π = 490.1 cm^2

11.) l = sqrt(r^2 + h^2) = sqrt(11^2 + 16^2) = sqrt(121 + 256) = sqrt(377) = 19m
6 0
3 years ago
125% of x is 60. What is x
Lunna [17]

Answer:

Step-by-step explanation:

1.put your percent over a 100 so

125%/100 then put 60 over x

2.then cross multiply 100x60=6000

3.then divide 6000 by 125 which is percent

4.your answer is-48

8 0
3 years ago
Read 2 more answers
Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar
horsena [70]

Answer:

P(A) = \frac{1}{9}

P(B) = \frac{1}{3}

P(C) = \frac{1}{729}

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

P(M) = \frac{1}{3}.

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is P(A) = \frac{1}{9}. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}.

C. If the probability that two people have been hired on a specific day of the week is 3(\frac{1}{3}) ^ 2, then the probability that 7 people have been hired on the same day is:

P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}

D. The probability is \frac{1}{729}. This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0
3 years ago
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