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Anton [14]
3 years ago
7

Helpp!!!! Give the relation and identify the x and y axis intercepts.

Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer:

(2, 0) and (6, 0)

Step-by-step explanation:

y = x^2 - 8 x + 12

To get the x intersept put y = 0

x^2 - 8 x + 12 = 0 \\\\x^2 - 6 x - 2 x + 12 = 0 \\\\x(x- 6) - 2(x - 6) = 0 \\\\(x - 2) (x - 6) = 0 \\\\x = 2 and x = 6

So, the intersepts are

(2, 0) and (6, 0)

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(x+7)^2+9=0<br><br> Find x with quadratics
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Answer:

x = -7 ±3i

Step-by-step explanation:

(x+7)^2+9=0

Subtract 9 from each side

(x+7)^2+9-9=0-9

(x+7)^2=-9

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(-9)

We know sqrt(ab) = sqrt(a) sqrt(b)

x+7 = ±sqrt(-1) sqrt(9)

We know that sqrt(-1) is the imaginary number i

x+7 = ±i *3

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Subtract 7 from each side

x+7-7 = -7 ±3i

x = -7 ±3i

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