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2 years ago

Evaluate the expression when m=3 and n=8. 40/n-m=

Mathematics

2 answers:

labwork [276]2 years ago

8 0

Answer:

The answer is 8

Step-by-step explanation:

If n = 8 and m = 3, 8 - 3 = 5.

40 ÷ 5 = 8

Hope this helps

yKpoI14uk [10]2 years ago

5 0

Answer:

Step-by-step explanation:

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kotegsom [21]

Answer: The one on the right. Each side is multiplied by 6, therefore they are similar.

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3 years ago

I need help :/ i have five questions

IrinaK [193]

Answer:

Step-by-step explanation:

1. The given equation is:

$\frac{3}{5}{\times}\frac{4}{5}$

Multiplying both the terms, we get

$\frac{12}{25}$

Option A is correct.

2. The given equation is:

$2\frac{1}{3}{\times}\frac{3}{4}$

Converting the improper fraction into the mixed fraction,

$\frac{7}{3}{\times}\frac{3}{4}$

= $\frac{7}{4}$

Option C is correct.

3. The given equation is:

$\frac{3}{16}{\times}\frac{4}{21}$

Multiplying both the terms, we get

= $\frac{1}{28}$

4. The given equation is:

$3\frac{8}{9}{\times}4\frac{4}{5}$

Converting the improper fraction into the mixed fraction,

$\frac{35}{9}{\times}\frac{24}{5}$

= $\frac{56}{3}$

5. One package contains= $5\frac{1}{4}=\frac{21}{4}$ pounds of raisins.

$4\frac{2}{3}$ packages contains= $4\frac{2}{3}{\times}5\frac{1}{4}$ pounds of raisins.

= $\frac{14}{3}{\times}\frac{21}{4}$

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3 years ago

Given the original number n. Multiply the number by 9. Add 99. Divide this sum by 9. Subtract the original number, n, from the q

tangare [24]

Answer:

Step-by-step explanation:

Hello,

Given the original number n.

$\large \boxed{n}$

Multiply the number by 9.

$\large \boxed{9n}$

Add 99.

$\large \boxed{9n+99}$

Divide this sum by 9.

$\large \boxed{\dfrac{9n+99}{9}=n+11}$

Subtract the original number, n, from the quotient.

$\large \boxed{n+11-n=11}$

Thank you.

4 0

2 years ago

(2y^3+5y^2-y+15) ÷ (y-4)

Sveta_85 [38]

ANSWER: 2y^2 + 13y +51 r(219/y-4)

picture explanation too:

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2 years ago

The matrix C=[1,-2_-3,7] was used to encode a phrase to [7,-28,-25,-35,-2_-21,107,90,123,17]. Find C^-1 and use it to decode the

posledela

$C= \left[\begin{array}{cc}1&-2\\-3&7\end{array}\right] \\ C^{-1}= \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \\ \left[\begin{array}{cc}7&2\\3&1\end{array}\right] \times \left[\begin{array}{ccccc}7&-28&-25&-35&-2\\-21&107&90&123&17\end{array}\right] \\ =\left[\begin{array}{ccccc}49-42&-196+214&-175+180&-245+246&-14+34\\21-21&-84+107&-75+90&-105+123&-6+17\end{array}\right] \\ =\left[\begin{array}{ccccc}7&18&5&1&20\\0&23&15&18&11\end{array}\right]$
is the required matrix.

6 0

2 years ago