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melisa1 [442]
3 years ago
8

What’s the answer to this? 4x-4=4x is it infinitive solution?

Mathematics
2 answers:
insens350 [35]3 years ago
5 0

Answer: There are no values of

x that make the equation true.

No solution

Step-by-step explanation:

emmasim [6.3K]3 years ago
3 0

Answer:

16 ?

Step-by-step explanation:

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What is the solution of (x+2)³/₄=27 ? <br> (A) x=27 (B) x=79 (C) x=81 (D) x=83
Molodets [167]

The solution (B) x=79.

Rewriting the equation to find the solution -

(x+2)³/₄=27

Raising both sides of the equation with exponent ⁴/₃

((x+2)³/₄)⁴/₃ = 27⁴/₃

Cancelling the exponents on Left Hand Side of the equation. Writing the value on Right Hand Side of the equation in exponent form

x + 2 =  (3³)⁴/₃

Cancelling 3 on Right Hand Side of the equation

x + 2 = 3⁴

Solving Right Hand Side of the equation

x + 2 = 81

Shifting 2 to Right Hand Side of the equation

x = 81 - 2

Performing subtraction on Right Hand Side of the equation

x = 79

Hence, the solution is (B) x=79.

Learn more about calculations on solution of x -

brainly.com/question/18356625

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8 0
1 year ago
IA6 Review<br> I NEED THE ANSWERS
vitfil [10]
Can you explain it or maybe take a picture?
4 0
3 years ago
Use the properties of equality to simplify the equation. Tell whether the equation has zero, one, or infinitely many solutions.
Ganezh [65]
Answer
One solution
8 0
3 years ago
-(-3,-2) and (1,6); m = 2<br> Plz help me
tensa zangetsu [6.8K]

m

=

−

2

,  (

3,

5

)

Find the value of  b

using the formula for the equation of a line.

b

=

11

Now that the values of  

m  (slope) and  b

(y-intercept) are known, substitute them into  

y

=

m

x

+

b  to find the equation of the line.   y

=

−

2

x

+

11

5 0
4 years ago
for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b
marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

               ⇒    300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

                                                = 101/2 (300+100)

                                                = 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

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7 0
1 year ago
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