The Reactance of a Capacitor is t<u>he resistance it has when alternating current (A/C) with a specific frequency (f) passes through it. </u>This is measured in ohms (Ω) and its formula is:
(1)
Where:
is the Reactance in ohms (Ω)
is the frequency of the alternating current in Hertz (
)
is the Capacitance of the Capacitor in Farad (
)
In this case we have a 25 mF capacitor with an applied frequency of 400 Hz.
Note 
Well, with the given data we have to solve (1):
Then:
XC=0.0159 Ω This is the Reactance of the Capacitor
Answer:
$1,519
Step-by-step explanation:
Given that :
Balance = principal = $520
Time (t) = 6 years
Annual. Interest rate (r) = 18% = 0.18
Using the compound interest formula:
A = P(1 + r/n)^nt
n = number of times interest is applied per period ; A = final amount
Since interest is compounded monthly, n = 12
A = 520(1 + 0.18/12)^(12 * 6)
A = 520(1 + 0.015)^72
A = 520(1.015)^72
A = 520(2.9211579)
A = 1519.0021
Hence, final amount = $1519
Hello :
<span>If f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
</span>(f+g)(x)= f(x) +g(x) = x/2-2 +2x²+x-3 = x/2 +2x²+x-5
(f+g)(x)= (x+4x²-2x-10) /2
(f+g)(x)= (4x²+3x-10)/2 = 2x²+3/2 x -5
1 gallon = 16 cups
Hope it helps you.
