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cricket20 [7]
3 years ago
13

A recipe for 1 batch of muffins included 2/3 cup of raisins. Ina made 2 1/2 batches of muffins. How many cups of raisins did she

use?
Mathematics
1 answer:
alexira [117]3 years ago
7 0
1 batch of muffins included 2/3 cups of raisins.  We can use this to set a proportion: 1 : 2/3.  That means for every 1 batch, she uses 2/3 cups of raisins.

Now, Ina made 2 1/2 batches.  To find out how, we need to look at our proportion again: 1 : 2/3.  Whatever operation you do to one side, you must do to the other.  So, to get 2 1/2 batches, we need to multiply the left side of the proportion, which is 1 batch, by 2 1/2 to get 2 1/2 batches.

BUT, we also need to multiply the other side, 2/3 cups, by 2 1/2.  We can start by converting this into an improper fraction, 5/2.  (Because 1=2/2, so 2=4/2, and 4/2+1/2=5/2.)  When multiplying fractions, you multiply the numerators together to get the new numerator, and the denominators to get the new denominator.  2*5=10, and 3*2=6.  Our new fraction is 10/6.  Since these are both divisible by 2, we simplify by dividing each side by 2 to get 5/3.  Finally, we can convert this into a mixed number: 1 2/3.  (Because 1=3/3 and 5/3 - 3/3 = 2/3, and 1 + 2/3 = 1 2/3.)  This is the cups of raisins she used.

Answer: She used 1 2/3 cups of raisins.
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Answer:

I think it will be 54.125%

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3 years ago
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A marching band wants to raise 20,000 at its annual fundraiser if they sell tickets for 20 a piece how many tickets will they ha
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1000 tickets because you would divide 20000 divided by 20 =1,000
8 0
3 years ago
HELP!!!!
ch4aika [34]

Answer:

8 y^{50}

Step-by-step explanation:

Given (64 y Superscript 100 Baseline) Superscript one-half.

Let us write it into an equation.

\left(64 y^{100}\right)^{\frac{1}{2}}

Apply radical rule: \sqrt[n]{a}=a^{\frac{1}{2}} and a^{m+n}=a^m+a^n

\begin{aligned}\left(64 y^{100}\right)^{\frac{1}{2}} &=\sqrt[2]{64 y^{100}} \\&=\sqrt[2]{8^{2} y^{50} y^{50}} \\&=\sqrt[2]{8^{2}\left(y^{50}\right)^{2}} \\&=8 y^{50}\end{aligned}

Hence, 8 y^{50} is equivalent to  (64 y Superscript 100 Baseline) Superscript one-half.

8 0
3 years ago
At one point the average price of regular unleaded gasoline was ​$3.41 per gallon. Assume that the standard deviation price per
Aleonysh [2.5K]

Answer:

a)  1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75

So we expected about 75% within two deviations from the mean

b) 1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

Lower = 3.41 -1.5*0.09 = 3.275

Upper = 3.41 +1.5*0.09 = 3.545

c) We can calculate how many deviations we are within the mean with the limits with this formula:

z =\frac{x-\mu}{\sigma}

And using the lower limit we got:

z = \frac{3.05-3.41}{0.09}=-4

And with the upper limit we got:

z = \frac{3.77-3.41}{0.09}=4

So then the value of k =4 and the percentage is given by:

1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375

Step-by-step explanation:

Previous concepts and Data given  

\mu =3.41 reprsent the population mean

\sigma=0.09 represent the population standard deviation

The Chebyshev's Theorem states that for any dataset

• We have at least 75% of all the data within two deviations from the mean.

• We have at least 88.9% of all the data within three deviations from the mean.

• We have at least 93.8% of all the data within four deviations from the mean.

Or in general words "For any set of data (either population or sample) and for any constant k greater than 1, the proportion of the data that must lie within k standard deviations on either side of the mean is at least: 1-\frac{1}{k^2}

Part a

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{2^2}= 1-0.25 = 0.75

So we expected about 75% within two deviations from the mean

Part b

For this case we can find the percentage required replaincg k =2 and we got:

1-\frac{1}{k^2} =1- \frac{1}{1.5^2}= 1-0.4444 = 0.556

So we expected about 55.6% within 1.5 deviations from the mean

And the limits are:

Lower = 3.41 -1.5*0.09 = 3.275

Upper = 3.41 +1.5*0.09 = 3.545

Part c

We can calculate how many deviations we are within the mean with the limits with this formula:

z =\frac{x-\mu}{\sigma}

And using the lower limit we got:

z = \frac{3.05-3.41}{0.09}=-4

And with the upper limit we got:

z = \frac{3.77-3.41}{0.09}=4

So then the value of k =4 and the percentage is given by:

1-\frac{1}{k^2} =1- \frac{1}{4^2}= 1-0.0625 = 0.9375

3 0
3 years ago
On a standardized exam, the scores are normally distributed with a mean of 300 and a standard deviation of 50. Find the z-score
Radda [10]

Answer:

z = -3

Step-by-step explanation:

<u>Use the formula for z-score</u>

z=\frac{x-\mu}{\sigma}\\\\z=\frac{150-300}{50}\\ \\z=\frac{-150}{50}\\ \\z=-3

This tells us that the person's score of 150 puts him/her 3 standard deviations below the mean of 300.

5 0
2 years ago
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