Please help fast

puteri [66]

Answer

396 miles and $28.71

8 0

3 years ago

is it possible to have a right triangle in which the sine of one of the angles is equal to the cosine of one of the angles? why?

stira [4]

Answer:

Yes , it is possible (see the explanation)

Step-by-step explanation:

we know that

In a right triangle, we have two complementary angles (their sum equal to 90 degrees)

so

If two angles are complementary, the cofunction identities state that the sine of one equals the cosine of the other and vice versa

<em>Example</em>

Suppose we have the right triangle ABC

The measure of angle C is 90 degrees

A and B are complementary angles

A+B=90°

therefore

sin(A)=cos(B)

sin(B)=cos(A)

8 0

4 years ago

(a + b)(a^2 - ab + b^2)

lidiya [134]

Answer:

(a^3-b^3)

Step-by-step explanation:

According to the formula

5 0

4 years ago

Read 2 more answers

Two fair, 6-sided dice are rolled, what is the probability that their product is perfect square

cricket20 [7]

Sample space of two fair 6 sided dice is 36.
Product = perfect square are (1, 1), (1, 4), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)
Probability that their product is perfect square = 7/36

8 0

3 years ago

A car company claims that its cars achieve an average gas mileage of at least 26 miles per gallon. A random sample of eight cars

motikmotik

Answer:

$t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value for this case is given by:

$p_v =P(t_{(7)}$

Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense

Step-by-step explanation:

Information given

$\bar X=25.5$ represent the sample mean

$s=1$ represent the sample standard deviation

$n=8$ sample size

$\mu_o =26$ represent the value to verify

$\alpha=0.06$ represent the significance level

t would represent the statistic (variable of interest)

$p_v$ represent the p value

Hypothesis to est

We want to test if the true mean is at least 26 mpg, the system of hypothesis would be:

Null hypothesis: $\mu \geq 25.5$

Alternative hypothesis: $\mu < 25.5$

The statistic for this case is given by;

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{25.5-26}{\frac{1}{\sqrt{8}}}=-1.414$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value for this case is given by:

$p_v =P(t_{(7)}$

Since the p value is higher than the significance level of 0.06 we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly less than 25.5 and then the claim makes sense

3 0

4 years ago