2 11/78 you just have to simply multiply 64/143 x2 because since it can't be subtracted. And after you multiply 64/143, you just have to subtract normally which is 128-21 and 286-208. Then since your answer came out to an improper fraction, so you have to simplify by dividing 107 divided by 78. Then you will get your answer which is 2 11/78.
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Find the distance between the points t(13, 1.6)t(13, 1.6) and v(5.4, 3.7)v(5.4, 3.7).
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The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:
Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:
Answer:
P(X 
74) = 0.3707
Step-by-step explanation:
We are given that the score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3.
Let X = Score of golfers
So, X ~ N(
)
The z score probability distribution is given by;
Z = 
~ N(0,1)
where, 
= population mean = 73
= standard deviation = 3
So, the probability that the score of golfer is at least 74 is given by = P(X 74)
P(X 74) = P( 
) = P(Z 0.33) = 1 - P(Z < 0.33)
= 1 - 0.62930 = 0.3707
Therefore, the probability that the score of golfer is at least 74 is 0.3707 .
Answer:
2 is the LCF :)
Step-by-step explanation:
All are divisible by 2. 2 is the lowest number than even numbers can be divided by.
