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3 years ago

HELP MEEEEE EASY DUE IN A MINSS What is the prime factorization of 990?

Mathematics

1 answer:

alex41 [277]3 years ago

3 0

Answer:

11 is one of the factors! The orange divisor(s) above are the prime factors of the number 990. If we put all of it together we have the factors 2 x 3 x 3 x 5 x 11 = 990.

Step-by-step explanation:

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Solution given:

The given equation of a line is

ax²+2hxy+by²=0

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ax²+2hxy+by²=0

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Substituting value of y

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Again.

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x²[a+2hm+Bm²]=0

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Taking coefficient of equation 1 &2.

equation 1. b 2h a b 2h

equation 2.A. -2h B A -2H

Doing criss cross multiplication

ignore first coefficient and repeat first and second

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$\frac{m²}{2hB}$ = $\frac{m}{aA-bB}$ = $\frac{1}{-2Hb-2hA}$

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m= $\frac{2hB+2Ha}{aA-bB}$ ....[*]

Taking 3rd & 2nd ratio,we get,

m= $\frac{aA-bB}{-2Hb-2hA}$ ....[#]

Again

Equating equation * &# we get;

$\frac{2hB+2Ha}{aA-bB}$ = $\frac{aA-bB}{-2Hb-2hA}$

(aA-bB)²=-4(hB+Ha)(Hb+HA)

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