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3 years ago

Convert 101 kilocalories into kilojoules.

Chemistry

1 answer:

siniylev [52]3 years ago

3 0

Answer:

422.584 kilojoules.

Explanation:

Easy, just know you stuff and you'll understand.

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Consider the following reaction, equilibrium concentrations, and equilibrium constant at

REY [17]

Answer:

Equilibrium concentration of $H_{2}O$ is 12.5 M

Explanation:

Given reaction: $C_{2}H_{4}+H_{2}O\rightleftharpoons C_{2}H_{5}OH$

Here, $K_{c}=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}][H_{2}O]}$

where $K_{c}$ represents equilibrium constant in terms of concentration and species inside third bracket represent equilibrium concentrations

Here, $[C_{2}H_{4}]=0.015M$ , $[C_{2}H_{5}OH]=1.69M$ and $K_{c}=9.0$

So, $[H_{2}O]=\frac{[C_{2}H_{5}OH]}{[C_{2}H_{4}]\times K_{c}}=\frac{1.69}{0.015\times 9.0}=12.5M$

Hence equilibrium concentration of $H_{2}O$ is 12.5 M

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3 years ago

The Earth, the Sun, and the rest of the solar system are almost unimaginably old when viewed on a human time scale. While modern

lord [1]

That makes the Earth, the Sun, and the rest of the solar system
something like 23 thousand times as old as the human species !

4 0

4 years ago

Read 2 more answers

There are 3.0 g of NO and 3.0 g of CO reacting. what is the limiting reactant ?

xxTIMURxx [149]

Answer:

NO will be the limiting reagent.

Explanation:

The balanced equation is:

2 NO + 2 CO → N₂ + 2 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

NO: 2 moles
CO: 2 moles
N₂: 1 mole
CO₂: 2 moles

Being the molar mass of each compound:

NO: 30 g/mole
CO: 28 g/mole
N₂: 28 g/mole
CO₂: 44 g/mole

Then by stoichiometry the following quantities of mass participate in each reaction:

NO: 2 moles* 30 g/mole= 60 g
CO: 2 moles* 28 g/mole= 56 g
N₂: 1 mole* 28 g/mole= 28 g
CO₂: 2 moles* 44 g/mole= 88 g

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, you can use a simple rule of three as follows: If 56 grams of CO react with 60 grams of NO, 3 grams of CO react with how much mass of NO?

$mass of NO=\frac{3 grams of CO*60 grams of NO}{56 grams of CO}$

mass of NO= 3.21 grams

But 3.21 grams of NO are not available, 3 grams are available. Since you have less moles than you need to react with 3 grams of CO, NO will be the limiting reagent.

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3 years ago

How much oxygen be required to produce 3.9 mol of water

timofeeve [1]

Answer:

1.95mol

Explanation:

First let us generate the equation for the reaction:

2H2 + O2 —> 2H2O

From the equation,

1mole of O2 reacted to produce 2moles of H2O.

Therefore, Xmol of O2 will react to produce 3.9 mol of H2O i.e

Xmol of O2 = 3.9/2 = 1.95mol

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3 years ago

Compare how a positively charged object and a negatively charged object interact with a neutral object:

nlexa [21]

In the area of positive charge, neutral body gets negative charge for making a dipole whereas when negative charge bought near neutral one, it gets positive charge for the same reason.........making polarization

8 0

4 years ago