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Artyom0805 [142]
3 years ago
13

How much oxygen be required to produce 3.9 mol of water

Chemistry
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

1.95mol

Explanation:

First let us generate the equation for the reaction:

2H2 + O2 —> 2H2O

From the equation,

1mole of O2 reacted to produce 2moles of H2O.

Therefore, Xmol of O2 will react to produce 3.9 mol of H2O i.e

Xmol of O2 = 3.9/2 = 1.95mol

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Answer:

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Explanation:

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Can anybody check my answer?
anzhelika [568]

Answer:

\boxed{\text{25. 20 L; 26. 49 K}}

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}

Calculations:

\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:  

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 ×  8.314 × T

2026 = 41.57T

T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}

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4 years ago
For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.
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Answer:

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2 years ago
Sodium has an atomic number of 11 and has a net charge of 0. When sodium combines with chlorine, it has a net charge of +1. Why?
Mamont248 [21]

Answer: Option (A) is the correct answer.

Explanation:

Atomic number of sodium is 11 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{1}.

In order to gain stability, sodium loses one electron and hence it forms a positive ion (Na^{+}).

Thus, we can conclude that when sodium combines with chlorine, it has a net charge of +1 because sodium loses a negative electron when forming chemical bonds.

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3 years ago
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Which of the following blackbody curves is representative of stars like our Sun?
Xelga [282]

Answer:

its letter b

Explanation:

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3 years ago
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