Answer:
56.2÷6.02×10^23
=9.34×10^23
Explanation:
Divide the given mass of the atom by the mass of an Atom (the avogadro's constant) to find the number of atoms in the given mass.
The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg
Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol
The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺
The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5
Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
= 13.65 x 10⁻⁵ mol
Molar mass of KIO₄ = 230 g/mol
Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
= 0.031395 g
= 31.395 mg
≈ 31.4 mg
Answer:
- <u>two molecules of ammonia are formed by the reaction of one nitrogen and three hydrogen molecules.</u>
Explanation:
The balanced chemical equation provides information on:
- <u>Reactants</u>: those are the compounds that appear of the left side of the equation, each with its chemical formula.
- <u>Products</u>: those are the compounds that appear on the right side of the equation, again, each with its chemical formula.
- <u>Ratio</u>: the coefficients of each compound (the number to the left of the chemical formula) represent the ratio of the number of molecules that react and are formed.
In the given equation you have:
- Equation: N₂ + 3H₂ → 2NH₃
- The coefficients are 1 for nitrogen, 3 for hydrogen, and 2 for ammonia. Hence, 2 molecules of ammonia are formed by the reaction of 1 molecule of nitrogen and 3 molecules of hydrogen.
