$1.10 per pound for the 1-pound bag.
$0.96 per pound for the 2-pound bag.
$0.92 per pound for the 3-pound bag.
As the quantity of sugar increases, the unit cost decreases.
Answer:
<h2>
0.0526ft/min</h2>
Step-by-step explanation:
Since the gravel being dumped is in the shape of a cone, we will use the formula for calculating the volume of a cone.
Volume of a cone V = πr²h/3
<em>If the diameter and the height are equal, then r = h</em>
V = πh²h/3
V = πh³/3
If the gravel is being dumped from a conveyor belt at a rate of 20 ft³/min, then dV/dt = 20ft³/min
Using chain rule to get the expression for dV/dt;
dV/dt = dV/dh * dh/dt
From the formula above, dV/dh = 3πh²/3
dV/dh = πh²
dV/dt = πh²dh/dt
20 = πh²dh/dt
To calculate how fast the height of the pile is increasing when the pile is 11 ft high, we will substitute h = 11 into the resulting expression and solve for dh/dt.
20 = π(11)²dh/dt
20 = 121πdh/dt
dh/dt = 20/121π
dh/dt = 20/380.133
dh/dt = 0.0526ft/min
This means that the height of the pile is increasing at 0.0526ft/min
the length of a side of a square is the square root of the area
side length = sqrt(164)
side length = 12.8062
Round the answer as needed
since it asks for approximate, it is probably going to be 13 inches
Answer:
The time after which the rocket hit the ground is 5 seconds
Step-by-step explanation:
Given as :
The distance of the cover by rocket at the height h = - 16 t² + 160 t
Let the time after which rocket hit the ground = T seconds
Now, When the rocket hits the ground, then at that time, the velocity of the rocket becomes zero.
I.e velocity = 
= 0
Or, v = = 0
Now, v =
Or, v = 
or, v = - 32 t + 160
Now, ∵ velocity of rocket after reaching the ground becomes zero
So, v = - 32 t + 160 = 0
Or, 32 t = 160
Or, t = 
∴ t = 5 sec
So, The time after which the rocket hit the ground = 5 sec
Hence The time after which the rocket hit the ground is 5 seconds answer
