Solution :
Demand for cola : 100 – 34x + 5y
Demand for cola : 50 + 3x – 16y
Therefore, total revenue :
x(100 – 34x + 5y) + y(50 + 3x – 16y)
R(x,y) = 

In order to maximize the revenue, set



.............(i)


.............(ii)
Solving (i) and (ii),
4 x (i) ⇒ 272x - 32y = 400
(ii) ⇒ (-<u>) 8x - 32y = -50 </u>
264x = 450
∴ 

So, x ≈ $ 1.70 and y = $ 1.99
R(1.70, 1.99) = $ 134.94
Thus, 1.70 dollars per cola
1.99 dollars per iced ted to maximize the revenue.
Maximum revenue = $ 134.94
Na bro i dont even know what’s that tbh
Answer:
Explanation:
The statement is expressed as
y
∝
1
x
inverse means
1
variable
To convert to an equation introduce k, the constant of variation.
y
=
k
×
1
x
⇒
y
=
k
x
To find k use the given condition that y = 8 when x = 4
8
=
k
4
⇒
k
=
4
×
8
=
32
⇒
equation is
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
∣
∣
∣
2
2
y
=
32
x
2
2
∣
∣
∣
−−−−−−−−−−−−
x
=
16
→
y
=
32
16
⇒
y
=
2
when
x
=
16
It wont let me see the pic sorry
try again
The numbers included in this interval are from -12/17 and on.