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k0ka [10]
3 years ago
7

Which inequality makes the statement below true? |-13 BLANK -13 O A. = O B. < OC. S O D. >

Mathematics
1 answer:
navik [9.2K]3 years ago
3 0

Answer:

Hey there the best answer would be A.=

Step-by-step explanation:

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What is the mode of this data set? 35,36,35,38,37,38,38,38,33,40,34,36,36,38,39,38,37,33,37,38,36,32,36,37,32
denpristay [2]

Answer:

38

Step-by-step explanation:

The most occuring number is the mode, which in this case is 38.

7 0
3 years ago
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300 ml over 15 min is what rate of ml per hour
Mama L [17]

Answer:

1200 ml per hour

Step-by-step explanation:

To compute what rate is 300 ml over 15 mins as a rate of ml per hour, we do a rule of 3, using a variable x as that amount of ml we don't know yet. We should have everything in the same units, so instead of writing 1 hour we write 60 minutes:

\frac{300~ml}{15~min}=\frac{x~ml}{60~mins}

Now we solve for x:

\frac{300~ml}{15~min}\cdot 60~mins=x~ml

\frac{18000~ml}{15} =x~ml

1200~ml =x~ml

And so, now that we know the value of x, the rate we wanted to find is

\frac{1200~ml}{60~mins}

Which is just 1200 ml per hour.

3 0
3 years ago
Stick a pencil down my licorice
Masteriza [31]
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8 0
3 years ago
What is the solution to 4+ 5ex+2 11?
BlackZzzverrR [31]

Answer:

x= 1/e or x= 0.367

Step-by-step explanation:

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3 0
3 years ago
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Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
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