The inequality is: x*0.75 + 3.00 < 20.00, where x represents the number of miles. When you solve the inequality, you get 22.66 miles. When you round up to 23 miles, you don't satisfy the inequality, so you have to round down to 22 miles.
Answer: (C) 22 miles
step by step explanation:
![\mathfrak{x}^{2}+{y}^{2}+16=0](https://tex.z-dn.net/?f=%5Cmathfrak%7Bx%7D%5E%7B2%7D%2B%7By%7D%5E%7B2%7D%2B16%3D0)
=[x2+16=0x26]
=[2x{y}^2{16}~0]
=[4×{y}^0{16}]
=[32x{y}^x]
Answer:
<h2>No solution : 0= -5</h2>
Step-by-step explanation:
![-3\left(x+1\right)=-3\left(x+1\right)-5\\\\\mathrm{Add\:}3\left(x+1\right)\mathrm{\:to\:both\:sides}\\\\-3\left(x+1\right)+3\left(x+1\right)=-3\left(x+1\right)-5+3\left(x+1\right)\\\\\mathrm{Simplify}\\\\0=-5\\\\\mathrm{The\:sides\:are\:not\:equal}\\\\\mathrm{No\:Solution}](https://tex.z-dn.net/?f=-3%5Cleft%28x%2B1%5Cright%29%3D-3%5Cleft%28x%2B1%5Cright%29-5%5C%5C%5C%5C%5Cmathrm%7BAdd%5C%3A%7D3%5Cleft%28x%2B1%5Cright%29%5Cmathrm%7B%5C%3Ato%5C%3Aboth%5C%3Asides%7D%5C%5C%5C%5C-3%5Cleft%28x%2B1%5Cright%29%2B3%5Cleft%28x%2B1%5Cright%29%3D-3%5Cleft%28x%2B1%5Cright%29-5%2B3%5Cleft%28x%2B1%5Cright%29%5C%5C%5C%5C%5Cmathrm%7BSimplify%7D%5C%5C%5C%5C0%3D-5%5C%5C%5C%5C%5Cmathrm%7BThe%5C%3Asides%5C%3Aare%5C%3Anot%5C%3Aequal%7D%5C%5C%5C%5C%5Cmathrm%7BNo%5C%3ASolution%7D)
Find a common denominator to subtract, so smallest common denimator between 7 and 3 is 21
multiply 4/7 by 3/3 and 2/3 by 7/7
12/21-14/21= -2/21
Okay, here we have this:
Considering the provided information and grades, we are going to calculate the requested GPA, so we obtain the following:
Then we will substitute in the following formula:
![GPA=\frac{Grades\ast Credits}{Total\text{ credits}}](https://tex.z-dn.net/?f=GPA%3D%5Cfrac%7BGrades%5Cast%20Credits%7D%7BTotal%5Ctext%7B%20credits%7D%7D)
Then:
![\begin{gathered} GPA=\frac{3.8\cdot5+1.9\cdot2+3.0\cdot5+2.8\cdot4}{16} \\ GPA=\frac{19+3.8+15+11.2}{16} \\ GPA=\frac{49}{16} \\ GPA=3.06 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20GPA%3D%5Cfrac%7B3.8%5Ccdot5%2B1.9%5Ccdot2%2B3.0%5Ccdot5%2B2.8%5Ccdot4%7D%7B16%7D%20%5C%5C%20GPA%3D%5Cfrac%7B19%2B3.8%2B15%2B11.2%7D%7B16%7D%20%5C%5C%20GPA%3D%5Cfrac%7B49%7D%7B16%7D%20%5C%5C%20GPA%3D3.06%20%5Cend%7Bgathered%7D)
Finally we obtain that the student's GPA for that term is approximately 3.06.