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Vsevolod [243]
3 years ago
11

What is the value of 7P3 ? A. 21 B. 35 C. 210 D. 840 i think a but idk

Mathematics
2 answers:
Aleksandr [31]3 years ago
6 0
The answer is C.
Here's why, nPr = n!/(n-r)!. Plug in 7 for n and 3 for r. And you get 7!/(7-3)!.
Thus, 7!/4! = (7*6*5*4*3*2*1)/(4*3*2*1), which simplifies to 7*6*5 = 210
mash [69]3 years ago
6 0

Answer  

Option (c) is correct

The value of  ^7P_3=210

Step-by-step explanation:

 Given : ^7P_3

We have to find the value of  ^7P_3

Consider ^7P_3

Permutation is defined as number of possibilities for choosing an ordered set  of r objects from a total of n objects.

^nP_r=\frac{n!}{\left(n-r\right)!}

put n = 7 and r = 3

We have,

^7P_3=\frac{7!}{\left(7-3\right)!}

Simplify, we have

=\frac{7!}{4!}

\quad \frac{n!}{\left(n-m\right)!}=n\cdot \left(n-1\right)\cdots \left(n-m+1\right),\:n>m

\frac{7!}{4!}=7\cdot \:6\cdot \:5=210

Thus, The value of  ^7P_3=210

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