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Galina-37 [17]
4 years ago
6

Question B_1 (15 points) Please define (describe) local variables and how they are used in computer programming ( e.g. In C, C )

. Please write clearly and use no more than 2 sentences. Question B_2 ( 15 points) Please define (describe) static variables and how they are used in computer programming ( e.g. In C, C ). Please write clearly and use no more than 2 sentences. Question
Computers and Technology
1 answer:
OverLord2011 [107]4 years ago
5 0

Answer and Explanation:

Static variables are variables that still maintain their values outside the score which they are declared. They are declared with the static keyword

Example:

<em>static int score = 30;</em>

Local variables are variables whose scope are restricted to a block. Their values are restricted to the block which they are declared in.

Example:

<em>void abd(){</em>

<em>int score;</em>

<em>}</em>

<em>score is a local variable to abcd() function</em>

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A compression scheme for long strings of bits called run-length encoding is described as follows: Rather than record each 0 and
Musya8 [376]

Answer: (B) Lossless compression

Explanation:

 According to the question, the given technique is the example of the lossless compression. The lossless compression is one of the technique that decompress the data into the original data form without any type of losses.

The lossless compression is the technique that usually compress the data, text and the databases. This technique also improve the compression rate helps in reconstruct the original data. It is used in various types of encoding methods, GNU tool and zip file.

3 0
4 years ago
Kevin is working on a financial project that involves a lot of statistical information. He needs software that allows him to ent
makvit [3.9K]

Answer: Spreadsheet Software

If Kevin would use a spreadsheet software, he will be able to input all of the statistical data and have the software generate graphs of the data that he has inputted into the spreadsheet. Using a spreadsheet software, Kevin will also have access to changing the graphs data whenever an anomaly has been detected.

Some of examples of these software would be:

  • Microsoft Excel
  • Open Office
  • Google Sheets
  • LibreOffice

8 0
3 years ago
UML is a graphical language that is used for designing and documenting software created within the _____________ framework. (a)
stealth61 [152]

Answer:

The answer is "option d".

Explanation:

UML stands for Unified Modeling Language. It is an OOPs based language that is used to design a graphic by software developers. This language can also be used to build diagrams and provide some tools to ready-to-use, interactive templates for users and other options are not correct that can be described as:

  • In option a, The Top-down approach is not followed by UML.
  • In option b, UML uses an object-oriented programming language that follows a bottom-up approach. It refers to a style of programming.
  • In option c, It does not use structured programming because it uses procedural languages.

7 0
3 years ago
What are three subject areas that are key to successfully working in the field of robotics
Novosadov [1.4K]

The brain ( computer science engineering)

The nervous system ( electrical engineering)

The body ( Mechanical engineering). The mechanical engineer is in the charge of the physical system that makes up the robot.

4 0
3 years ago
Data Structure in C++
agasfer [191]

The code .cpp is available bellow

#include<iostream>

using namespace std;

//declaring variables

void merge(int* ip, int sz, int* opt, bool opt_asc); //merging

int* mergesort(int* ip, int sz);

void mergesort(int *ip, int sz, int* opt, bool opt_asc);

void merge(int* ip, int sz, int* opt, bool opt_asc)

{

  int s1 = 0;

  int mid_sz = sz / 2;

  int s2 = mid_sz;

  int e2 = sz;

  int s3 = 0;

  int end3 = sz;

  int i, j;

   

  if (opt_asc==true)

  {

      i = s1;

      j = e2 - 1;

      while (i < mid_sz && j >= s2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (i != mid_sz)

      {

          while (i < mid_sz)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i++;

          }

      }

      if (j >= s2)

      {

          while (j >= s2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j--;

          }

      }

  }

  else

  {

      i = mid_sz - 1;

      j = s2;

      while (i >= s1 && j <e2)

      {

          if (*(ip + i) > *(ip + j))

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

          else if (*(ip + i) <= *(ip + j))

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

      if (i >= s1)

      {

          while (i >= s1)

          {

              *(opt + s3) = *(ip + i);

              s3++;

              i--;

          }

      }

      if (j != e2)

      {

          while (j < e2)

          {

              *(opt + s3) = *(ip + j);

              s3++;

              j++;

          }

      }

  }

   

  for (i = 0; i < sz; i++)

      *(ip + i) = *(opt + i);

}

int* mergesort(int* ip, int sz)

{

  int* opt = new int[sz];

   

  mergesort(ip, sz, opt, true);

  return opt;

}

void mergesort(int *ip, int sz, int* opt, bool opt_asc)

{

  if (sz > 1)

  {

      int q = sz / 2;

      mergesort(ip, sz / 2, opt, true);

      mergesort(ip + sz / 2, sz - sz / 2, opt + sz / 2, false);

      merge(ip, sz, opt, opt_asc);

  }

}

int main()

{

  int arr1[12] = { 5, 6, 9, 8,25,36, 3, 2, 5, 16, 87, 12 };

  int arr2[14] = { 2, 3, 4, 5, 1, 20,15,30, 2, 3, 4, 6, 9,12 };

  int arr3[10] = { 10, 9, 8, 7, 6, 5, 4, 3, 2, 1 };

  int *opt;

  cout << "Arays after sorting:\n";

  cout << "Array 1 : ";

  opt = mergesort(arr1, 12);

  for (int i = 0; i < 12; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 2 : ";

  opt = mergesort(arr2, 14);

  for (int i = 0; i < 14; i++)

      cout << opt[i] << " ";

  cout << endl;

  cout << "Array 3 : ";

  opt = mergesort(arr3, 10);

  for (int i = 0; i < 10; i++)

      cout << opt[i] << " ";

  cout << endl;

  return 0;

}

4 0
4 years ago
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