All categories

3 years ago

I need help with this

Mathematics

1 answer:

emmasim [6.3K]3 years ago

6 0

Answer:

Here,

Angle TUV + Angle NUV=TUV

By substituting the provided or given value ls in the question we obtain,

1+38x+66 Degree= 105x

1+66 Degree= 67x

67 Degree= 67x

1 Degree = x

x = 1 Degree

Therefore

Angle TUN=1+38x=39

Angle NUV=66 Degree

Therefore

1+38x+66 Degree= 105x

=39 Degree+66 Degree= 105 Degree

Therefore

Angle TUV=105 Degree

You might be interested in

4(2x - 1) = 3x + 6 Solve for x. Show steps with sentences supporting each step.

mr Goodwill [35]

Answer:

x = 2

Step-by-step explanation:

4(2x - 1) = 3x + 6

Simplify

8x - 4 = 3x + 6

Subtract 3x from both sides

8x - 3x - 4 = 3x - 3x + 6

5x - 4 = 6

Add 4 to both sides

5x - 4 + 4 = 6 + 4

5x = 10

Divide both sides by 5

5x/5 = 10/5

x = 2

5 0

2 years ago

Read 2 more answers

What’s the variance

creativ13 [48]

A is the right answer

8 0

3 years ago

a crowbar of 2cm is used to lift an object if 800N. if the effort arm is 260cm. calculate the effort applied.

Gelneren [198K]

Answer:

solution:Here

Given,

Load=800 N

Load distance=2cm

Effort distance=260cm

Effort applied=?

We know that,

Load × Load distance = Effort × Effort distance

or, 800×2 = e × 260

or,1600 = 260e

or,e = 1600/260

Thus, e = 6.15 N

Hence, The effort applied = 6.15 N

Hope this answer helped you..

Please mark me as brainliest

8 0

9 months ago

Solve: (a+b+c) (a+b-c)

Katen [24]

Answer:

Step-by-step explanation:

Solve:

(a+b+c) (a+b-c)=

(a²+ab-ac+ab+b²-bc+ac+bc-c²)=

a²+ab-ac+ab+b²-bc+ac+bc-c²=

a²+2ab+0ac+b²+0bc-c²=

a²+2ab+b²-c²

7 0

2 years ago

Read 2 more answers

The graph of the function f(x) = (x - 3)(x + 1)

djyliett [7]

Answer:

The graph is positive and decreasing for all real values of x where x < -1

Step-by-step explanation:

we have

$f(x)=(x-3)(x+1)$

The function is a vertical parabola open up

The roots (x-intercepts) are x=3 and x=-1

The vertex is the point (1,-4 ) is a minimum

using a graphing tool

see the attached figure

we know that

In the interval (-∞,-1) ---> the function is positive and decreasing

In the interval (-1,1) ---> the function is negative and decreasing

In the interval (1,3) ---> the function is negative and increasing

In the interval (3,∞) ---> the function is positive and increasing

therefore

The graph is positive and decreasing for all real values of x where x < -1

8 0

3 years ago