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3 years ago

What is the equation of this line?

Mathematics

2 answers:

JulsSmile [24]3 years ago

8 0

Find the gradient of the line using any two points on the line as
let point A(2,-2) point B(-2,-4)
using $m= \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }$
as the y-intercept is -3

Mamont248 [21]3 years ago

3 0

(0, -3)(2, -2)
slope = (-2 + 3)/(2-0) = 1/2

b = -3
equation
y = 1/2x - 3

answer is A
<span>y = 1/2x - 3</span>

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Solve for m k=mvsquared/2

Lerok [7]

Answer:

$m=\frac{2k}{v^{2} }$

Step-by-step explanation:

4 0

2 years ago

The graph of F(x) can be stretched vertically and flipped over the x axis to produce the graph of G(x) if F(x)=x^2 which of the

ladessa [460]

Answer:

g(x) = -5x²

(option B)

Step-by-step explanation:

we know that our original graph, f(x) = x² is a parabola.

So, we can consider what happens when we adjust the function/equation of a parabola.

when we "vertically stretch" a parabola, we are increasing the value of x.

think of it this way: the steepness of a slope is rise over run. If we rise ten, and run one, that's going be a lot more steep than if we rise 1, run 1.

Let's say our x = 5

if f(x)=x²

f(5) = 25

> y value / steepness is 25

f(x) = 3x²

f(5) = 75

> y value / steepness is 75

So, we are looking for an equation with an increase in x present.

When a parabola has been flipped over the x-axis, we know that the original equation now includes a negative

suppose that x = 1

if y = x² ; y = 1² = 1

if y = -(x²) ; y = -(1²) ; y = -1

So, when we set x to be negative, we make our y-values end up as negative also (which makes the graph look as if it has been flipped upside-down)

This means that we are looking for a function with a negative x value.

So, we are looking for a negative x-value that is multiplied by a number >1

The graph that fits our requirements is g(x) = -5x²

hope this helps!!

6 0

2 years ago

Help solving this math question

olga_2 [115]

22. B) $65,000,000 per year.

23. B) Education.

Step-by-step explanation:

Step 1; To find the average rate of change in annual budget between the two given years. We divide the difference in values for the two years by the period in between the two years. In 2008, the budget was $358,708,000 while in 2010 it was $488,106,000. The period in between was 2 years i.e 2009 and 2010.

The average rate of change = $\frac{488,106,000-358,708,000}{2}$ = $\frac{129,398,000}{2}$ = $64,699,000 per year.

So the average rate of change was $64,699,000 which approximately equals option B. $65,000,000.

Step 2; To find the human resources program's 2007 to 2010 ratio we divide the value in 2007 to the value in 2010. To find the other similar ratio, we divide the value in 2007 to the value in 2010 for all the other programs and determine which is closest to the human resources program.

Human resources program ratio = $\frac{4,051,050}{5,921,379}$ = 0.6841,