V=LWH
SA=2(LW+LH+WH)
V=240
first check that they are 240 volume
multiply numbers they should equal 240
the first one (A) can be eliminated since the dimentions are the same and therefor the surface areas are the same
2nd one check so far
3rd one (C) 6*4*15=360 which is wrong so eliminate this one
4th (d) 12*6*5=360 which is not 240 so eliminate
answer is B
<h2>
Answer with explanation:</h2>
It is given that:
f: R → R is a continuous function such that:
∀ x,y ∈ R
Now, let us assume f(1)=k
Also,
( Since,
f(0)=f(0+0)
i.e.
f(0)=f(0)+f(0)
By using property (1)
Also,
f(0)=2f(0)
i.e.
2f(0)-f(0)=0
i.e.
f(0)=0 )
Also,
i.e.
f(2)=f(1)+f(1) ( By using property (1) )
i.e.
f(2)=2f(1)
i.e.
f(2)=2k
f(m)=f(1+1+1+...+1)
i.e.
f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)
i.e.
f(m)=mf(1)
i.e.
f(m)=mk
Now,

Also,
i.e. 
Then,

(
Now, as we know that:
Q is dense in R.
so Э x∈ Q' such that Э a seq
belonging to Q such that:
)
Now, we know that: Q'=R
This means that:
Э α ∈ R
such that Э sequence
such that:

and


( since
belongs to Q )
Let f is continuous at x=α
This means that:

This means that:

This means that:
f(x)=kx for every x∈ R
So 8w=4c and 2c=3g. divide the first equation by 2 and you get 4w=2c. merge the two equation give you 4w=2c=3g, or 4w=3g. multiply 4 on both sides give you 16w=12g. So 16 widgets equal how 12 goof-ups?
12x/15-10x/15
=2x/15 is your answer