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Alekssandra [29.7K]
3 years ago
7

Calculate the number of repetitions of the β-oxidation pathway required to fully convert a 18-carbon activated fatty acid to ace

tyl-scoa molecules.
Chemistry
1 answer:
Anna35 [415]3 years ago
4 0
The number of repetition of the Beta oxidation requires to fully convert 18 carbon activated fatty acid to Acetyl COA molecule is NINE.
Beta oxidation of fatty acid involves oxidative removal of successive two carbon units in the form of acetlyl COA, starting from the carboxyl end of the fatty acyl chain. Thus, a fatty acid which has 18 carbons will have to undergo nine repetition of beta oxidation before it is reduced to an acetyl COA.
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A student in the lab accidentally poured 45 mL of water into a graduated cylinder containing 15 mL of 3.0 M HCL. What is the con
Bumek [7]

Answer:

The correct approach is "1 M".

Explanation:

The given values are:

Volume of HCL,

V₁ = 45 ml

In prepared solution,

V₂ = 15 ml

Concentration,

C₁ = ?

C₂ = 3.0 M

As we know,

⇒  V_1C_1=V_2C_2

or,

⇒      C_1=\frac{V_2C_2}{V_1}

On substituting the values, we get

⇒           =\frac{15\times 3}{45}

⇒           =\frac{45}{45}

⇒           =1 \ M

4 0
3 years ago
Why empty gas cylinder is dangerous?​
Irina-Kira [14]

Answer:Empty gas cylinders are dangerous because the can explode and cause hazards and empty gas cylinders with open valves can breath,this can cause explosion.

Explanation:

4 0
3 years ago
How many neutrons make up one of these potassium atoms <br>​
julia-pushkina [17]

Answer:

4

Explanation:

I dont know that's all you need

5 0
3 years ago
Coal power plants burn large amounts of coal, C(s), in an 02(g) atmosphere to generate electricity. The chemical reaction respon
Stella [2.4K]

Answer:

1.85 × 10⁸ L

Explanation:

Coal power plants burn large amounts of coal, C(s), in an O₂(g) atmosphere to generate electricity. The chemical reaction responsible for producing this energy is shown below:

C(s) + O₂(g) → CO₂(g)

Determine the volume of CO₂ in liters produced when 100 metric ton of C(s) is completely burned in an O₂ atmosphere. The density of CO₂ is 1.98 kg/m³ (1 metric ton = 1000 kg: 1 m³ = 1000 L)

We can establish the following relations:

  • 1 metric ton = 1000 kg
  • 1 kg = 1000 g
  • The molar mass of C(s) is 12.01 g/mol
  • The molar ratio of C(s) to CO₂(g) is 1:1
  • The molar mass of CO₂(g)  is 44.01 g/mol
  • 1.98 kg of CO₂(g)  occupy a volume of 1 m³ (density = 1.98 kg/m³)
  • 1 m³ = 1000 L

The volume of CO₂ produced when 100 metric ton of C(s) react is:

100metric/tonC.\frac{10^{6}gC}{1metric/tonC} .\frac{1molC}{12.01gC} .\frac{1molCO_{2}}{1molC} .\frac{44.01 \times 10^{-3} kgCO_{2}}{1molCO_{2}} .\frac{1m^{3}CO_{2}}{1.98kgCO_{2}} .\frac{1000LCO_{2}}{1m^{3}CO_{2}} =1.85 \times 10^{8} LCO_{2}

3 0
3 years ago
How many moles of air are there in a 3 L container at 1 atm pressure and 294 K?Use PV=nRT
Keith_Richards [23]

The ideal gas law states: PV=nRT

If we put in the data.

1\cdot7=n\cdot8.31\cdot294 \\n=\boxed{2.865\cdot10^{-3}mol}=\boxed{2.865mmol}

Hope this helps.

r3t40

3 0
3 years ago
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