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Andru [333]
3 years ago
8

What is the ground-state electron configuration of a neutral atom of cobalt? express your answer in condensed form, in order of

increasing orbital energy. for example, [he]2s22p2 would be entered as [he]2s^22p^2 ?
Chemistry
1 answer:
Anastaziya [24]3 years ago
8 0

the atomic number of cobalt is 27

when writing the electronic configuration of cobalt, electrons are arranged into energy shells and subenergy shells .

the complete electron configuration for cobalt is as follows

Co - 1s² 2s² 2p⁶ 3s² 3p⁶  3d⁷ 4s²

we can write this in the condensed form

writing in condensed form is when you write the noble gas symbol for the noble gas with the closest atomic number

Ar is the closest noble gas with atomic number of 18

electron configuration for Ar is as follows

Ar - 1s² 2s² 2p⁶ 3s² 3p⁶

so we can substitute Ar in the electron configuration upto the 18th electron


so the condensed electron configuration for Co is as follows

[Ar] 3d⁷ 4s² 

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It is A because it has a lower activation emery than like B
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3 years ago
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Which area is most likely to support a marsh ecosystem?.
andriy [413]

Answer:

A location that is humid, would most likely support a marsh ecosystem.

Explanation:

The Florida Everglades are an example of a marsh :)

"Marshes are a type of wetland ecosystem where water covers the ground for long periods of time. Marshes are dominated by herbaceous plants, such as grasses, reeds, and sedges."

5 0
3 years ago
an engineer wishes to design a container that will hold 12.0 mol of ethane at a pressure no greater than 5.00x10*2 kPa and a tem
OleMash [197]

Answer:

The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.

Explanation:

Assume that ethane behaves as an ideal gas under these conditions.

By the ideal gas law,

P\cdot V = n\cdot R\cdot T,

\displaystyle V = \frac{n\cdot R\cdot T}{P}.

where

  • P is the pressure of the gas,
  • V is the volume of the gas,
  • n is the number of moles of particles in this gas,
  • R is the ideal gas constant, and
  • T is the absolute temperature of the gas (in degrees Kelvins.)

The numerical value of R will be 8.314 if P, V, and T are in SI units. Convert these values to SI units:

  • P =\rm 5.00\times 10^{2}\;kPa = 5.00\times 10^{2}\times 10^{3}\; Pa = 5.00\times 10^{5}\; Pa;
  • V shall be in cubic meters, \rm m^{3};
  • T = \rm 52.0 \textdegree C = (52.0 + 273.15)\; K = 325.15\; K.

Apply the ideal gas law:

\displaystyle \begin{aligned}V &= \frac{n\cdot R\cdot T}{P}\\ &= \frac{12.0\times 8.314\times 325.15}{5.00\times 10^{5}}\\ &= \rm 0.0649\; m^{3} \\ &= \rm (0.0649\times 10^{3})\; L \\ &=\rm 64.9\; L\end{aligned}.

4 0
4 years ago
A solution is prepared from 8 grams of acetic acid (CH2CO2H) and 725 grams of water. What is the molarity of this solution?
Andrews [41]
Hello!

First, we can assume the density of water to be 1 g/mL, so the volume of water would be 725 mL. The density of Acetic Acid (Pure) is 1,05 g/mL so 8 grams would represent 7,61 mL

Now we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:

[CH_3CO_2H]=\frac{8 g_{CH_3CO_2H}  }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }

[CH_3CO_2H]=0,1818 M

So, the concentration of acetic acid would be 0,1818 M

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