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Svetradugi [14.3K]
3 years ago
12

Two data sets are shown set a: 45,65,66,67,68,68,69,70,70 set b: 40,41,43,45,46,47,48,49,49 the mean of set a is 65.6 the mean o

f set b is 45
(please help!!)

Mathematics
1 answer:
azamat3 years ago
7 0

Answer:

Set A : 45, 65, 66, 67 ,68, 68, 69, 70, 70

Median = 68

Set B : 40, 41, 43, 45, 46, 47, 48, 49, 49

Medain = 46

When 45 is removed from both

Set A : 65, 66, 67 ,68, 68, 69, 70, 70

Median = 68

Set B : 40, 41, 43, 46, 47, 48, 49, 49

Medain = 46.5

Set A : 45, 65, 66, 67 ,68, 68, 69, 70, 70

Mean = 65.33

Set B : 40, 41, 43, 45, 46, 47, 48, 49, 49

Mean = 45.33

when 45 is removed from both

Set A :  65, 66, 67 ,68, 68, 69, 70, 70

Mean  = 67.875

Set B : 40, 41, 43, 46, 47, 48, 49, 49

Mean = 45.38

The difference between median of A and B decreases because the median of set B increases.

The difference between mean of A and B increases because the mean of set A increases.

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HACTEHA [7]

This question is incomplete, the complete question is;

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y2 = 2x, x = 2y; about the y-axis

Answer:

V = π (512/15)

Step-by-step explanation:

Given that;

region of rotation

y² = 2x, x = 2y

Region is rotated about y-axis as shown in the image

for the point of intersection,

y²/2 = 2y

y² - 4y = 0

y(y-4) = 0

∴ y = 0, y = 4

so the region lies in 0 ≤ y ≤ 4

Now cross section area of washer is

A(y) = π(outer radius)² = π(inner radius)²

A(y) = π(2y)² - π(y²/2)²

A(y) = π(4y²) - π(y⁴/4)

A(y) = π(4y² - (y⁴/4))

now volume of the solid of revolution is

V = ⁴∫₀ A(y) dy

V = ⁴∫₀ π(4y² - (y⁴/4))dy

V =  π {4⁴∫₀ y² - 1/4⁴∫₀y⁴ dy }

V = π { 4/3 [y³]₀⁴ - 1/20 [y⁵]₀⁴ }

V = π { 4/3 [4]₀⁴ - 1/20 [4]₀⁴ }

V = π { 4/3 [64]₀⁴ - 1/20 [1024]₀⁴ }

V = π { 256/3 - 1024/20 }

V = π { (5120 - 3072) / 60 }

V = π (512/15)

8 0
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Answer:

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castortr0y [4]

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3 years ago
What would this equal too look at the screen shot
jekas [21]

Given:

The figure of two parallel lines MP and QS.

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