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podryga [215]
3 years ago
9

Which of the expressions below has a 1 in the tenths place of the product? Select all that apply. A) 18.3 x 7 B) 6.5 x 4.31 C) 8

.54 x 2.3 D) 5.4 x 2.8
Mathematics
1 answer:
n200080 [17]3 years ago
3 0

Answer: A) 18.3 x 7 and D) 5.4 x 2.8

Step-by-step explanation:

A) 18.3 x 7 = 128.10

We can infer that 1 is in the tenths place.

B) 6.5 x 4.31 = 28.015

We can infer that 1 is not in the tenths place but rather the hundredths place.

C) 8.54 x 2.3 = 19.642

We can infer that 1 is not in the tenths place.

D) 5.4 x 2.8 = 15.12

We can infer that 1 is in the tenths place.

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Several intervals can be combined into one region using the "set union" operation, ∪∪, which is represented as "u" in webwork. f
alekssr [168]

Write the set of points from  -6 to 0 but excluding  -4  and 0 as a union of intervals

First we take  the interval  -6 to 0. In that -4  and 0 are excluded.

So we split the interval -6 to 0.

Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.

Interval becomes [-6,-4) . It says -6 included but -4 excluded.

Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets

(-4,0)

Now we take union of both intervals

[-6,-4) U (-4,0)  --- Interval from  -6 to 0 but excluding  -4  and 0



7 0
3 years ago
Help pleaseeeee?????
Artyom0805 [142]
They would be identical so it would be 114
4 0
2 years ago
Write the equation of the line given the slope and a point through the line passes
Anuta_ua [19.1K]

Answer:

1.) Y = 5/3 X + 4

2.) Y = 9/4 X - 27/4

Step-by-step explanation:

Given the slope and the coordinate, linear equation of a line can be expressed by using general linear equation. Which is

Y = MX + C

Where the

Slope M = 5/3

Coordinate = (-3,-1) in which

X = -3, Y = -1

Substitute X, Y and M into the general linear equation to achieve C

-1 = 5/3(-3) + C

-1 = - 5 + C

C = 5 - 1

C = 4

Substitute C and M back into the general linear equation.

Therefore, the equation of the line given the slope and a point through the line passes 5/3, and (-3,-1) to be

Y = 5/3 X + 4

2.) Also,

Slope M = 9/4

Coordinate = (3,0) where X = 3, Y = 0

Substitute X, Y and M into the general linear equation to obtain C

0 = 9/4 (3) + C

C = - 27/4

Substitutes C and M back into the general linear equation

Therefore, the equation of the line given the slope and a point through the line passes 9/4 and (3,0)

Y = 9/4 X - 27/4

4 0
2 years ago
Create an equivalent expression using the drop downs below 4(32 – 4).
GaryK [48]

Answer:

7x

Step-by-step explanation:

It equals 28 just like the problem with parentheses, 7x .

3 0
2 years ago
Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
3 0
2 years ago
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