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Anit [1.1K]
3 years ago
14

Check all that apply

Mathematics
1 answer:
Bogdan [553]3 years ago
7 0

Answer:

i think its a,c,e

Step-by-step explanation:

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Joshua is raking leaves. He has of the yard left to rake. He splits the remaining yard into sections that are the size of the en
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Answer: 2???????

It's too short. Write at least 20 characters to explain it well.

3 0
3 years ago
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How does graphing linear inequalities differ from graphing linear equations?​
Ivan

Explanation:

When the inequality symbol is replaced by an equal sign, the resulting linear equation is the boundary of the solution space of the inequality. Whether that boundary is included in the solution region or not depends on the inequality symbol.

The boundary line is included if the symbol includes the "or equal to" condition (≤ or ≥). An included boundary line is graphed as a solid line.

When the inequality symbol does not include the "or equal to" condition (< or >), the boundary line is not included in the solution space, and it is graphed as a dashed line.

Once the boundary line is graphed, the half-plane that makes up the solution space is shaded. The shaded half-plane will be to the right or above the boundary line if the inequality can be structured to be of one of these forms:

  • x > ...   or   x ≥ ...   ⇒ shading is to the right of the boundary
  • y > ...   or   y ≥ ...   ⇒ shading is above the boundary

Otherwise, the shaded solution space will be below or to the left of the boundary line.

_____

Just as a system of linear equations may have no solution, so that may be the case for inequalities. If the boundary lines are parallel and the solution spaces do not overlap, then there is no solution.

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The attached graph shows an example of graphed inequalities. The solutions for this system are in the doubly-shaded area to the left of the point where the lines intersect. We have purposely shown both kinds of inequalities (one "or equal to" and one not) with shading both above and below the boundary lines.

6 0
3 years ago
Put these in order from least to greatest 1/2, 1/3, 2/5, 0.6 , o.3
Aleks04 [339]

Answer:

0.3, 1/3, 2/5, 1/2, 0.6

Step-by-step explanation:

6 0
3 years ago
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I need to find the zeros to these two problems and I have no idea how
Iteru [2.4K]
If you have a graphing calculator just put in the equation in 'y=' (not the i equation), and then go to 2nd trace and see where the y=0, those numbers under the x column are the zeros. For the first one, the zeros are: -1, .5, and 2.8. For the second question the zeros are: -3 and about 1.9. The zeros with a decimal are estimations.
7 0
3 years ago
50 POINTS - A Builder intends placing 7 equally spaced homes on a semicircular plot. If the circle has a diameter of 400 feet, w
Ray Of Light [21]

Answer:  89.7 ft

<u>Step-by-step explanation:</u>

Find the arc length (s) of the semi-circle.  Then divide that length by 7.

s = r · θ      where r is the radius and θ is the angle in radians

s = (400 ÷ 2) · π        <em>(radius is diameter divided by 2)</em>

  = 200π

  = 628.3

The length of the arc is 628.3 ft.  Divide that by 7 to find the distance between each home.

628.3 ÷ 7 = 89.7

3 0
3 years ago
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